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kuskey
Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH
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 Posted: Sun Jan 09, 2011 5:41 am Post subject: Jan 9 VH |
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Both of these are 1-steppers:
Type 1 UR using 45s in r68c13 making r8c1<>45
w-wing using 26s in c23 with strong link 2 in c4 making r2c2 and r5c3<>6 |
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Marty R.
Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
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| Posted: Sun Jan 09, 2011 6:10 am Post subject: |
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Also:
Skyscraper on 2 in rows 35
XY-Wing (782, pivot r5c9), flightless with transport, r3c5<>2 |
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Sun Jan 09, 2011 2:03 pm Post subject: |
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| I used two Type 4 URs for 76 and 45. |
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Ema Nymton
Joined: 17 Apr 2009
Posts: 89
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| Posted: Sun Jan 09, 2011 3:05 pm Post subject: |
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Basic steps arrive at:
| Code: |
+------------+--------------+----------+
| 3 4 7 | 9 268 68* | 1 5 28 |
| 8 256 26 | 2457 1 47 | 3 9 27 |
| 1 25 9 | 3 25 78 | 78 6 4 |
+------------+--------------+----------+
| 7 26 1 | 28 4 9 | 68 3 5 |
| 9 3 26 | 1 28 5 | 678 4 78 |
| 45 8 45 | 67 67 3 | 2 1 9 |
+------------+--------------+----------+
| 2 9 3 | 57 57 1 | 4 8 6 |
| 456 7 45 | 468 3 468 | 9 2 1 |
| 46 1 8 | 46 9 2 | 5 7 3 |
+------------+--------------+----------+
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If r1c5 is '8' then r5c9 must be '8'. If r1c9 is '8' than r5c5 must be '8'.
R1c6 and r5c7 cannot be '8'. R1c6 must be '6'.
Ema Nymton
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Sun Jan 09, 2011 4:33 pm Post subject: |
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Ema: Not sure from your logic why R1c6 cannot initially be considered an '8' - but in any event this seems to be a “what if” or “trial and error”solution as opposed to a “technique” (like wings, URs, ERs, colouring, etc.). I guess you could argue that “trail and error” is also a technique but this kind of solution is rarely offered on this Forum.
Cheers, Craig |
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kuskey
Joined: 10 Dec 2008
Posts: 141
Location: Pembroke, NH
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| Posted: Sun Jan 09, 2011 8:17 pm Post subject: Jan 9 VH |
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| Ema; simply take it for what it is, an x-wing on 8 in r15c59, eliminating 8 at r1c6 and r5c7. |
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Ema Nymton
Joined: 17 Apr 2009
Posts: 89
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| Posted: Sun Jan 09, 2011 8:31 pm Post subject: |
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| cgordon wrote: | Ema: Not sure from your logic why R1c6 cannot initially be considered an '8' - but in any event this seems to be a “what if” or “trial and error”solution as opposed to a “technique” (like wings, URs, ERs, colouring, etc.). I guess you could argue that “trail and error” is also a technique but this kind of solution is rarely offered on this Forum.
Cheers, Craig |
The logic is simple. In column 6 and column 9, '8' can be in only r1 or r5. If r1c6 were '8', then r5c5 and r5c9 are the only remaining cells that could be '8'.
Ema Nymton
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cgordon
Joined: 04 May 2007
Posts: 769
Location: ontario, canada
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| Posted: Sun Jan 09, 2011 9:20 pm Post subject: |
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| Quote: | | The logic is simple. |
It was simpler to follow the solution once Kuskey pointed out it is an x-wing. For me that's the whole point of "labelling" techniques. |
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