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Puzzle 11/08/13: ~ Extreme BBDB!!!

 
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daj95376



Joined: 23 Aug 2008
Posts: 3855

PostPosted: Sat Aug 13, 2011 10:12 pm    Post subject: Puzzle 11/08/13: ~ Extreme BBDB!!! Reply with quote

Update: I just discovered that this puzzle can be solved as an XY-rated puzzle.

Code:
 +-----------------------+
 | 5 . 6 | . . . | 3 . . |
 | . 9 . | . 3 . | . 6 . |
 | 3 . 8 | . . . | 9 . 1 |
 |-------+-------+-------|
 | . . . | 9 . . | . . . |
 | . 1 . | . 5 . | . 2 . |
 | . . . | . . . | 1 . 8 |
 |-------+-------+-------|
 | 1 . 4 | . . 3 | 8 5 . |
 | . 3 . | . 1 . | 4 9 2 |
 | . . 9 | . . 4 | . 1 . |
 +-----------------------+

Play this puzzle online at the Daily Sudoku site
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Luke451



Joined: 20 Apr 2008
Posts: 310
Location: Southern Northern California

PostPosted: Sun Aug 14, 2011 3:17 pm    Post subject: Reply with quote

Just a foolish solution here, a case of finding what you look for.

1. x-wing 4
2. x-wing 8
3. 7s: r3c8=r1c9-r7c9=r7c2 =>r3c2<>7

Leaves this position for an all-oddagon finish:
Code:
 *--------------------------------------------------------------------*
 | 5      247    6      | 1      247    9      | 3      8      47     |
 | 47     9      1      | 478    3      78     | 2      6      5      |
 | 3      24     8      | 567    2467   2567   | 9      47     1      |
 |----------------------+----------------------+----------------------|
 |*67     4678   237    | 9      24678  1      | 5      347   *67+4   |
 | 4678   1      37     | 34678  5      678    | 67     2      9      |
 | 9      4567   2357   | 367    2467   267    | 1      347    8      |
 |----------------------+----------------------+----------------------|
 | 1     *67     4      | 2      9      3      | 8      5      67     |
 |*67+8   3      57     | 5678   1      5678   | 4      9      2      |
 | 2      5678   9      | 567    678    4      | 67     1      3      |
 *--------------------------------------------------------------------*

4. (67)oddagon with a pause:
(8)r8c1=(4)r4c9-(4=7)r1c9-r1c2=r2c1-(7=6)r4c1 =>r8c1<>67
5. (47)oddagon r1c29, r36c8, r6c2
(5)r6c2=(2)r1c2-(2=4)r3c2 =>r6c2<>4

'Course, could have gone all w-wing, but how odd would that have been? Smile
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peterj



Joined: 26 Mar 2010
Posts: 974
Location: London, UK

PostPosted: Mon Aug 15, 2011 7:52 am    Post subject: Reply with quote

Luke, nice oddagon -and nice MUG elsewhere!

Fwiw, the two (67) bivalues are in a sort of w-wing loop which makes lots of eliminations... from Luke's grid...
Code:
w-wing-looped (6=7)r4c1 - r2c1=r1c2 - (7=6)r8c2 - r8c9=r4c9 - loop ; r46c2<>67, r8c1<>67, r4c5<>6, r9c2<>7

(Still need a wing or something to finish)

So not odd but loopy!
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