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		| Clement 
 
 
 Joined: 24 Apr 2006
 Posts: 1113
 Location: Dar es Salaam Tanzania
 
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				|  Posted: Wed Jan 11, 2012 11:38 pm    Post subject: Jan 12 VH |   |  
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				| W-Wing 89 with strong link 9 in col 7; r8c5<>8 solves it. |  | 
	
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Thu Jan 12, 2012 2:38 am    Post subject: |   |  
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				| Using a standard VH move, XYZ-Wing (379), pivot r1c5; r2c5<>9. |  | 
	
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		| roaa 
 
 
 Joined: 18 Apr 2009
 Posts: 112
 Location: Sweden
 
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				|  Posted: Thu Jan 12, 2012 9:12 am    Post subject: |   |  
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				| The xy-wing 389 with pivot r2c5 forces r1c5<>3 which solves it. |  | 
	
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		| arkietech 
 
 
 Joined: 31 Jul 2008
 Posts: 1834
 Location: Northwest Arkansas USA
 
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				|  Posted: Thu Jan 12, 2012 9:28 am    Post subject: |   |  
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				|  	  | Code: |  	  | *--------------------------------------------------* | 57   59   4    | 6    379  39   | 2    8    1    |
 | 68   2    3    | 1    89   5    | 49   469  7    |
 | 78   69   1    |b478  2   a4-8  | 5    369  39   |
 |----------------+----------------+----------------|
 | 4    1    6    | 2    5   e89   | 3    7    89   |
 | 9    8    7    | 3    4    1    | 6    5    2    |
 | 2    3    5    |d89   6    7    | 1    49   489  |
 |----------------+----------------+----------------|
 | 56   56   89   |c48   1    2    | 7    349  349  |
 | 1    7    89   | 5    38   348  | 49   2    6    |
 | 3    4    2    | 79   79   6    | 8    1    5    |
 *--------------------------------------------------*
 s-wing
 (4)r3c6=(4)r3c4-(4=8)r7c4-(8)r6c4=(8)r4c6 => r3c6<>8
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		| Orkamat 
 
 
 Joined: 20 Dec 2011
 Posts: 10
 Location: Winnipeg, Canada
 
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				|  Posted: Sun Jan 15, 2012 4:04 am    Post subject: |   |  
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				| UR r4 & r6, r6c9 = 4 also does the trick 
 That makes 3 VHs in a row that I've solved all by my lonesome.
   
 --Orkamat the ex-noob
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		| Luke451 
 
 
 Joined: 20 Apr 2008
 Posts: 310
 Location: Southern Northern California
 
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				|  Posted: Sun Jan 15, 2012 5:28 pm    Post subject: |   |  
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				|  	  | Orkamat wrote: |  	  | UR r4 & r6, r6c9 = 4 also does the trick | 
 Is this the pattern to which you refer?
 
  	  | Code: |  	  | *--------------------------------------------------* | 57   59   4    | 6    379  39   | 2    8    1    |
 | 68   2    3    | 1    89   5    | 49   469  7    |
 | 78   69   1    | 478  2    48   | 5    369  39   |
 |----------------+----------------+----------------|
 | 4    1    6    | 2    5   *89   | 3    7   *89   |
 | 9    8    7    | 3    4    1    | 6    5    2    |
 | 2    3    5    |*89   6    7    | 1    49  *89+4 |
 |----------------+----------------+----------------|
 | 56   56   89   | 48   1    2    | 7    34   349  |
 | 1    7    89   | 5    38   348  | 49   2    6    |
 | 3    4    2    | 79   79   6    | 8    1    5    |
 *--------------------------------------------------*
 
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		| Orkamat 
 
 
 Joined: 20 Dec 2011
 Posts: 10
 Location: Winnipeg, Canada
 
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				|  Posted: Sun Jan 15, 2012 8:16 pm    Post subject: |   |  
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				|  	  | Luke451 wrote: |  	  |  	  | Orkamat wrote: |  	  | UR r4 & r6, r6c9 = 4 also does the trick | 
 Is this the pattern to which you refer?
 
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 Yes. Not your garden-variety "rectangle," as the left-side squares share a box rather than a column, but the same logic applies ... unless my brain has turned to mush again.
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		| Luke451 
 
 
 Joined: 20 Apr 2008
 Posts: 310
 Location: Southern Northern California
 
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				|  Posted: Sun Jan 15, 2012 9:11 pm    Post subject: |   |  
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				| Hi, Orkamat, you're on the right track there, but garden-variety is the way to go with unique rectangles. 
 You need four cells that share two boxes, two rows and two columns.
 
 There's no one here that has not made some variation of this mistake, so don't feel badly.
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		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
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				|  Posted: Sun Jan 15, 2012 9:48 pm    Post subject: |   |  
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				| Let me add one thing, which may not be necessary. The idea behind Unique Rectangles is if all four cells were the same pair, 89 in this case, then the numbers could be interchanged and thus you'd have two solutions, whereas the puzzle is created to have one unique solution. 
 With the position of these four cells, the numbers could not be interchanged because invalidities would result.
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