| View previous topic :: View next topic   | 
	
	
	
		| Author | 
		Message | 
	
	
		muppetman74
 
 
  Joined: 18 Nov 2011 Posts: 6
 
  | 
		
			
				 Posted: Thu Apr 24, 2014 5:13 pm    Post subject: could somebody help me with a tough mini sudoku | 
				     | 
			 
			
				
  | 
			 
			
				- - 2   - 1 5
 
1 - -   2 6 - 
 
- - -   - 5 -
 
- - 3   1 2 -
 
- 4 -   5 3 -
 
- - -   6 4 -
 
 
I think there might be a triple somewhere but i can't see it. | 
			 
		  | 
	
	
		| Back to top | 
		 | 
	
	
		  | 
	
	
		Marty R.
 
 
  Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
  | 
		
			
				 Posted: Thu Apr 24, 2014 6:25 pm    Post subject:  | 
				     | 
			 
			
				
  | 
			 
			
				I have no experience with mini sudokus, but I'm assuming the rules are the same as the regular 9x9, except this is a 6x6.
 
 
I copied your numbers onto a grid and filled in each empty cell with the possible candidates. There is indeed a triple, but I don't know if you want to know where it is or just confirmation that there is one. 
 
 
Hint: the triple is in a column, not a row. | 
			 
		  | 
	
	
		| Back to top | 
		 | 
	
	
		  | 
	
	
		muppetman74
 
 
  Joined: 18 Nov 2011 Posts: 6
 
  | 
		
			
				 Posted: Thu Apr 24, 2014 9:31 pm    Post subject:  | 
				     | 
			 
			
				
  | 
			 
			
				thanks Marty i will give the puzzle another look with your kind hint.
 
 
I'll repost tomorrow with either a thank you or a polite request for another clue!  
 
 
thanks
 
 
iain | 
			 
		  | 
	
	
		| Back to top | 
		 | 
	
	
		  | 
	
	
		muppetman74
 
 
  Joined: 18 Nov 2011 Posts: 6
 
  | 
		
			
				 Posted: Thu Apr 24, 2014 9:39 pm    Post subject: eureka | 
				     | 
			 
			
				
  | 
			 
			
				ah.
 
 
hidden pair in column 2?
 
 
1&2 i think
 
 
thanks again.
 
 
And thanks for being so thoughtful as to not just give me the answer. | 
			 
		  | 
	
	
		| Back to top | 
		 | 
	
	
		  | 
	
	
		keith
 
 
  Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
  | 
		
			
				 Posted: Sat Aug 09, 2014 2:35 pm    Post subject:  | 
				     | 
			 
			
				
  | 
			 
			
				Take a look at where 4 must fit in C3 and C4. R2C6 is not 4 and the puzzle is solved.
 
 
Keith | 
			 
		  | 
	
	
		| Back to top | 
		 | 
	
	
		  | 
	
	
		 |