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VH+ 122221

 
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immpy



Joined: 06 May 2017
Posts: 519

PostPosted: Wed Dec 22, 2021 6:34 pm    Post subject: VH+ 122221 Reply with quote

Hello all, enjoy the puzzle. Merry Christmas!

Code:

+-------+-------+-------+
| . 6 1 | 2 5 . | . . . |
| . 9 7 | . 8 6 | . . . |
| 3 . . | . . 7 | 9 6 . |
+-------+-------+-------+
| . . 9 | 8 2 . | . . . |
| . 5 . | 6 3 1 | . 9 . |
| . . . | . 9 4 | 5 . . |
+-------+-------+-------+
| . 7 3 | . . . | . . 9 |
| . . . | . 6 . | 1 3 . |
| . . . | . 7 3 | 4 5 . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site

cheers...immp
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Thu Dec 23, 2021 7:15 am    Post subject: Reply with quote

Thanks Immp and Merry Christmas to you !

I will leave after basics to others and white out my solution. Decided on a less conventional one.

Quote:
It's the march of the <28> pairs. Quite a few on the grid after basics and many can be linked.

What's interesting is being able to link the <28> pincer pairs in r5c9 with r8c1. The whole "bridge" consists only of six <28> pairs. What is nice is that they toggle each other so that if r5c9 is 2 then r9c1 must be 8 and of course vice versa.

This means a double elimination of 2 and 8 at r5c1 leaving only 7 in that square and stte.



[Corrected x 2 - Diolch Tomos !]


Last edited by Mogulmeister on Thu Dec 23, 2021 10:09 pm; edited 5 times in total
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TomC



Joined: 30 Oct 2020
Posts: 280
Location: Wales

PostPosted: Thu Dec 23, 2021 9:37 am    Post subject: Reply with quote

Mogulmeister wrote:
Thanks Immp and Merry Christmas to you !

I will leave after basics to others and white out my solution. Decided on a less conventional one.

Quote:
It's the march of the <28> pairs. Quite a few on the grid after basics and many can be linked.

What's interesting is being able to link the <28> pincer pairs in r5c9 with r8c1. The whole "bridge" consists only of six <28> pairs. What is nice is that they toggle each other so that if r5c9 is 2 then r9c1 must be 8 and of course vice versa.

This means a double elimination of 2 and 8 at r1c5 leaving only 7 in that square and stte.


Very similar solution, started off with a <14> UR to then leave with a lot of <28>'s

But I think you mean r5c1 in your post!

Merry Christmas to all
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Thu Dec 23, 2021 11:46 am    Post subject: Reply with quote

I did mean r5c1! Not r1c5. Too much Christmas cheer I suspect! The UR also comes first.
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TomC



Joined: 30 Oct 2020
Posts: 280
Location: Wales

PostPosted: Thu Dec 23, 2021 7:30 pm    Post subject: Reply with quote

No problem, I found that r5c1<> 2 and this solves it, but didn't notice that it could also be not 8

Tomos
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Mogulmeister



Joined: 03 May 2007
Posts: 1151

PostPosted: Thu Dec 23, 2021 10:09 pm    Post subject: Reply with quote

Iíve made the second correction ! Thanks!
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