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immpy
Joined: 06 May 2017 Posts: 570
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Posted: Thu Jun 16, 2022 8:26 pm Post subject: Butterfly Pattern VH+ |
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Hello all, enjoy the puzzle.
Code: |
+-------+-------+-------+
| . . . | . . . | . . . |
| . . . | 9 8 3 | . . . |
| 9 5 . | 2 7 6 | . 1 3 |
+-------+-------+-------+
| . 4 . | . . . | . 8 . |
| . 6 8 | 1 . 7 | 4 5 . |
| . . 5 | . . . | 6 . . |
+-------+-------+-------+
| . . . | 3 . 5 | . . . |
| . 1 . | . . . | . 7 . |
| . 9 . | . 4 . | . 2 . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site
cheers...immp |
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Clement
Joined: 24 Apr 2006 Posts: 1110 Location: Dar es Salaam Tanzania
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Posted: Fri Jun 17, 2022 10:35 am Post subject: Butterfiy Pattern VH+ |
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Code: |
+------------------+-----------------+--------------------+
| 8 3 a67 | 45 15 14 | 2 9 6-7 |
| 67 2 1 | 9 8 3 | 57 46 4567 |
| 9 5 4 | 2 7 6 | 8 1 3 |
+------------------+-----------------+--------------------+
| 3 4 9 | 56 56 2 | 17 8 e17 |
| 2 6 8 | 1 3 7 | 4 5 9 |
| 1 7 5 | 48 9 48 | 6 3 2 |
+------------------+-----------------+--------------------+
| 467 8 b267 | 3 c126 5 | 9 46 d146 |
| 456 1 236 | 68 26 9 | 35 7 4568 |
| 56 9 36 | 7 4 18 | 135 2 1568 |
+------------------+-----------------+--------------------+
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(7)r1c3 = (7-2)r7c3 = (2-1)r7c5 = r7c9 - (1=7)r4c9 => - 7r1c9; stte |
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TomC
Joined: 30 Oct 2020 Posts: 349 Location: Wales
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Posted: Fri Jun 17, 2022 11:08 am Post subject: |
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Similar solution to Clement, a=6 to solve
Code: |
+----------------+---------------+------------------+
| 8 3 67 | 45 15 14 | 2 9 b67 |
| a67 2 1 | 9 8 3 | 57 46 4567 |
| 9 5 4 | 2 7 6 | 8 1 3 |
+----------------+---------------+------------------+
| 3 4 9 | 56 56 2 | 17 8 c17 |
| 2 6 8 | 1 3 7 | 4 5 9 |
| 1 7 5 | 48 9 48 | 6 3 2 |
+----------------+---------------+------------------+
| x467 8 267 | 3 126 5 | 9 x46 x146 |
| 456 1 236 | 68 26 9 | 35 7 4568 |
| 56 9 36 | 7 4 18 | 135 2 1568 |
+----------------+---------------+------------------+
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Play this puzzle online at the Daily Sudoku site
If a=7, b=7, c=1 leads to <46> "triple" in r7c189 |
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Clement
Joined: 24 Apr 2006 Posts: 1110 Location: Dar es Salaam Tanzania
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Posted: Fri Jun 17, 2022 11:52 am Post subject: |
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TomC wrote: | Similar solution to Clement, a=6 to solve
Code: |
+----------------+---------------+------------------+
| 8 3 67 | 45 15 14 | 2 9 b67 |
| a67 2 1 | 9 8 3 | 57 46 4567 |
| 9 5 4 | 2 7 6 | 8 1 3 |
+----------------+---------------+------------------+
| 3 4 9 | 56 56 2 | 17 8 c17 |
| 2 6 8 | 1 3 7 | 4 5 9 |
| 1 7 5 | 48 9 48 | 6 3 2 |
+----------------+---------------+------------------+
| x467 8 267 | 3 126 5 | 9 x46 x146 |
| 456 1 236 | 68 26 9 | 35 7 4568 |
| 56 9 36 | 7 4 18 | 135 2 1568 |
+----------------+---------------+------------------+
|
Play this puzzle online at the Daily Sudoku site
If a=7, b=7, c=1 leads to <46> "triple" in r7c189 | I think c=(1)r4c9 leads to pair( 4|6)r7c89 which sets r7c1 to 7 which can be written as a chain in Eureka Notation as:
7r2c1 - r2c79 = r1c9 - (7=1)r4c9 - (1=4|6)r7c89 - (4|6=7)r7c1 - (7=6)r2c1 => - 7r2c1; stte |
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TomC
Joined: 30 Oct 2020 Posts: 349 Location: Wales
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Posted: Fri Jun 17, 2022 12:14 pm Post subject: |
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Thanks for the notation Clement, I didn't think you needed a chain when three <46> pairs appear in one row
I probably should have explained it---- If a=7, x=<46>, b=7, c=1, x=<46> |
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dongrave
Joined: 06 Mar 2014 Posts: 564
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Posted: Fri Jun 17, 2022 7:50 pm Post subject: |
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Very interesting! And I noticed that if you take Clement's contradictory chain and apply the typical trick (which I learned from him and Marty) of beginning the chain one cell over, you'll end up with a forcing chain with pincers on both ends.
In this case it would be:
7r2c79 = r1c9 - (7=1)r4c9 - (1=4|6)r7c89 - (4|6=7)r7c1 => r2c1 <> 7; stte. |
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