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Oct 22 VH

 
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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 868
Location: Rimini, Italy

PostPosted: Sat Oct 22, 2022 9:55 am    Post subject: Oct 22 VH Reply with quote

Hi everyone,

Code:

+---------------+-------------+-----------+
| 2    9   45   | 7   34  35  | 8   1 6   |
| 58   1   6    | 259 48  259 | 459 3 7   |
| 578  3   4578 | 569 468 1   | 459 2 59  |
+---------------+-------------+-----------+
| 358  4   1    | 69  2   689 | 59  7 359 |
| 9    6   2    | 3   5   7   | 1   4 8   |
| 3578 57  578  | 4   1   89  | 2   6 359 |
+---------------+-------------+-----------+
| 1    257 57   | 8   37  235 | 6   9 4   |
| 4    257 9    | 256 67  256 | 3   8 1   |
| 6    8   3    | 1   9   4   | 7   5 2   |
+---------------+-------------+-----------+

Play this puzzle online at the Daily Sudoku site

Quote:
XY-Wing 4,5,8 in r1c3,r2c15 and -4 in r1c5


Ciao Gianni
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TomC



Joined: 30 Oct 2020
Posts: 349
Location: Wales

PostPosted: Sat Oct 22, 2022 11:44 am    Post subject: Reply with quote

Sometimes eliminating the impossible can solve a puzzle

Remove <4> from r3c3 to solve
Code:

+----------------+----------------+-------------+
| 2    9    45   |  7    34   35  | 8    1  6   |
| 58   1    6    |  259  48   259 | 459  3  7   |
| 578  3   x4578 |  569  468  1   | 459  2  59  |
+----------------+----------------+-------------+
| 358  4    1    | c69   2    689 | 59   7  359 |
| 9    6    2    |  3    5    7   | 1    4  8   |
| 3578 57  a578  |  4    1   b89  | 2    6  359 |
+----------------+----------------+-------------+
| 1    257  57   |  8    37   235 | 6    9  4   |
| 4    257  9    |  256  67   256 | 3    8  1   |
| 6    8    3    |  1    9    4   | 7    5  2   |
+----------------+----------------+-------------+
Quote:
If x=4, a=8, b=9, c=6 leads to a <59> pair in three cells r3c479

Cool
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Greenvilleguy



Joined: 01 Jul 2022
Posts: 23
Location: US

PostPosted: Wed Oct 26, 2022 12:40 pm    Post subject: Oct 22 VH Reply with quote

I need more help with this one. I don't see why you can eliminate the 4 in R3C3.
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dongrave



Joined: 06 Mar 2014
Posts: 563

PostPosted: Wed Oct 26, 2022 2:28 pm    Post subject: Re: Oct 22 VH Reply with quote

Greenvilleguy wrote:
I need more help with this one. I don't see why you can eliminate the 4 in R3C3.

Tom's solution goes as follows:

If r3c3 is 4 then it's not 8 so r6c3 is 8, so r6c6 is not 8 so it's 9, so r4c4 is not 9 so it's 6,
so r3c4 is not 6 so it's 5 or 9, but r3c7 is also 5 or 9 (because it's not 4 because r3c3 is 4), but r3c9 is also 5 or 9!
But we can't have 3 cells in row 3 with just the candidates 5 and 9 in them therefore r3c3 cannot be 4.
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