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July 3 very hard..stuck

 
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weeder



Joined: 07 Jul 2006
Posts: 1

PostPosted: Fri Jul 07, 2006 8:24 pm    Post subject: July 3 very hard..stuck Reply with quote

OK..I know I am missing the obvious. Thanks

1B7F|E-8D|53--|----
-2-0|45F1|-79-|AD--
-5--|7263|D-1C|-F--
--4-|0-BC|-8-F|---7

-C--|F8-6|4-73|--0-
76-E|D0-2|9F--|43--
3F8-|54-B|2-E-|7--9
0-5-|37-E|---D|--F1

B0-7|C--4|8---|-A-F
4--1|-6-9|F--7|-85
--F8|---7|--09|2-4-
-9--|83-F|----|--7-

D---|2F30|-5--|-E--
F---|1ED8|---2|--A-
-8E3|-C45|--F-|B-1D
-1--|-B7A|ED-8|F-C3
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David Bryant



Joined: 29 Jul 2005
Posts: 559
Location: Denver, Colorado

PostPosted: Fri Jul 07, 2006 11:19 pm    Post subject: Column on block interaction Reply with quote

Hi, weeder! Welcome to the forum.

In the position you posted, you need to concentrate on column 9, and on box 15 (bottom row of 4x4 boxes, right of center).

-- The "0" in column 9 can only appear in box 15 -- that is, at r14c9 or at r15c9.

-- This means that you can eliminate "0" as a possibility at r15c10 & r15c12, in particular.

-- This reveals a triplet {6, 9, A} in row 15, leaving "2" as the sole candidate at r15c1. And right after that you'll find a "2" at r16c14 and a "0" at r16c3 ... that should be enough to get you rolling again. dcb

PS There's also a quintet of values {6, 8, B, C, D} lurking in five cells in box 8 (extreme right, second row of 4x4 boxes). That will allow you to identify r5c14 = 5 (sole candidate, after eliminating "B").
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Suppen



Joined: 05 Jun 2015
Posts: 4
Location: 3044 Marie Street Baltimore, MD 21202

PostPosted: Thu Jun 18, 2015 8:39 am    Post subject: July 3 very hard stuck Reply with quote

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