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Earl
Joined: 30 May 2007 Posts: 677 Location: Victoria, KS
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Posted: Sat Mar 29, 2008 12:18 pm Post subject: March 29 DB |
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The March 29 DB can be colored in 8's to solve R6C9 and the puzzle.
Earl
Code: |
+-------+-------+-------+
| . . . | 9 . 1 | . . 7 |
| 7 . . | . 4 . | . . . |
| . 3 . | 2 . . | . . 9 |
+-------+-------+-------+
| . 7 . | . 5 3 | . 6 2 |
| . . . | . . . | . . . |
| 4 2 . | 6 1 . | . 5 . |
+-------+-------+-------+
| 3 . . | . . 7 | . 1 . |
| . . . | . 2 . | . . 5 |
| 9 . . | 3 . 4 | . . . |
+-------+-------+-------+
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Play this puzzle online at the Daily Sudoku site |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Mar 29, 2008 1:43 pm Post subject: |
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If you confine yourself to pencil marks only for cells that have two candidates, you will uncover a number of pairs, and then an easy to spot XY-wing.
If you look much harder, there is a Type 4 UR, but it does not help in the solution.
Keith |
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storm_norm
Joined: 18 Oct 2007 Posts: 1741
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Posted: Sat Mar 29, 2008 6:47 pm Post subject: |
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definitely thought the UR was a harder route of travel. I thought it was rare that strong link within the same box on 8 would provide a color elimination. |
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Marty R.
Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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Posted: Sat Mar 29, 2008 7:09 pm Post subject: |
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I don't know if I made a lucky mistake, but this solved with basic moves only.
I tried Keith's method of putting in pencil marks only in two-candidate cells. I don't know if that makes solving easier, just saves some work, or something else. |
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keith
Joined: 19 Sep 2005 Posts: 3355 Location: near Detroit, Michigan, USA
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Posted: Sat Mar 29, 2008 10:00 pm Post subject: |
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Marty R. wrote: | I don't know if I made a lucky mistake, but this solved with basic moves only.
I tried Keith's method of putting in pencil marks only in two-candidate cells. I don't know if that makes solving easier, just saves some work, or something else. |
Marty,
Here is my point, perhaps: If you solve all the singles, and fill in all the candidates, you are here:
Code: | Grid 1:
+----------------------+----------------------+----------------------+
| 2 4568 4568 | 9 3 1 | 4568 48 7 |
| 7 1569 1569 | 8 4 56 | 1356 2 136 |
| 1568 3 14568 | 2 7 56 | 14568 48 9 |
+----------------------+----------------------+----------------------+
| 18 7 189 | 4 5 3 | 189 6 2 |
| 1568 15689 135689 | 7 89 2 | 13489 3489 1348 |
| 4 2 389 | 6 1 89 | 7 5 38 |
+----------------------+----------------------+----------------------+
| 3 468 2 | 5 689 7 | 4689 1 468 |
| 68 468 7 | 1 2 689 | 34689 3489 5 |
| 9 15 15 | 3 68 4 | 2 7 68 |
+----------------------+----------------------+----------------------+ |
If you only fill in the cells with two candidates, you will get to here:
Code: | Grid 2:
+---------+---------+---------+
| 2 . . | 9 3 1 | 56 48 7 |
| 7 . . | 8 4 56| . 2 . |
| . 3 . | 2 7 56| . 48 9|
+---------+---------+---------+
| 18 7 . | 4 5 3 | . 6 2 |
| . . . | 7 89 2 | . 39 . |
| 4 2 . | 6 1 89| 7 5 38|
+---------+---------+---------+
| 3 . 2 | 5 . 7 | . 1 . |
| 68 . 7 | 1 2 89| . 39 5 |
| 9 15 15| 3 68 4 | 2 7 68|
+---------+---------+---------+ |
The solved cells are the same, the XY-wing that eliminates <9> in R5C5 is very obvious, and the puzzle is solved.
I prefer to go from Grid 2 to Grid 1 if necessary. If you prefer to simplify Grid 1, that's personal choice.
But, here, the two-candidate cells are all that is needed. I prefer to do only the two-candidate cells first; then, if need be, the three-candidate cells.
Keith |
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