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March 29 DB

 
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Earl



Joined: 30 May 2007
Posts: 677
Location: Victoria, KS

PostPosted: Sat Mar 29, 2008 12:18 pm    Post subject: March 29 DB Reply with quote

The March 29 DB can be colored in 8's to solve R6C9 and the puzzle.

Earl


Code:

+-------+-------+-------+
| . . . | 9 . 1 | . . 7 |
| 7 . . | . 4 . | . . . |
| . 3 . | 2 . . | . . 9 |
+-------+-------+-------+
| . 7 . | . 5 3 | . 6 2 |
| . . . | . . . | . . . |
| 4 2 . | 6 1 . | . 5 . |
+-------+-------+-------+
| 3 . . | . . 7 | . 1 . |
| . . . | . 2 . | . . 5 |
| 9 . . | 3 . 4 | . . . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Sat Mar 29, 2008 1:43 pm    Post subject: Reply with quote

If you confine yourself to pencil marks only for cells that have two candidates, you will uncover a number of pairs, and then an easy to spot XY-wing.

If you look much harder, there is a Type 4 UR, but it does not help in the solution.

Keith
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Sat Mar 29, 2008 6:47 pm    Post subject: Reply with quote

definitely thought the UR was a harder route of travel. I thought it was rare that strong link within the same box on 8 would provide a color elimination.
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Sat Mar 29, 2008 7:09 pm    Post subject: Reply with quote

I don't know if I made a lucky mistake, but this solved with basic moves only.

I tried Keith's method of putting in pencil marks only in two-candidate cells. I don't know if that makes solving easier, just saves some work, or something else.
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keith



Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA

PostPosted: Sat Mar 29, 2008 10:00 pm    Post subject: Reply with quote

Marty R. wrote:
I don't know if I made a lucky mistake, but this solved with basic moves only.

I tried Keith's method of putting in pencil marks only in two-candidate cells. I don't know if that makes solving easier, just saves some work, or something else.


Marty,

Here is my point, perhaps: If you solve all the singles, and fill in all the candidates, you are here:
Code:
Grid 1:
+----------------------+----------------------+----------------------+
| 2      4568   4568   | 9      3      1      | 4568   48     7      |
| 7      1569   1569   | 8      4      56     | 1356   2      136    |
| 1568   3      14568  | 2      7      56     | 14568  48     9      |
+----------------------+----------------------+----------------------+
| 18     7      189    | 4      5      3      | 189    6      2      |
| 1568   15689  135689 | 7      89     2      | 13489  3489   1348   |
| 4      2      389    | 6      1      89     | 7      5      38     |
+----------------------+----------------------+----------------------+
| 3      468    2      | 5      689    7      | 4689   1      468    |
| 68     468    7      | 1      2      689    | 34689  3489   5      |
| 9      15     15     | 3      68     4      | 2      7      68     |
+----------------------+----------------------+----------------------+

If you only fill in the cells with two candidates, you will get to here:
Code:
Grid 2:
+---------+---------+---------+
| 2  .  . | 9  3  1 | 56 48 7 |
| 7  .  . | 8  4  56| .  2  . |
| .  3  . | 2  7  56| .  48  9|
+---------+---------+---------+
| 18 7  . | 4  5  3 | .  6  2 |
| .  .  . | 7  89 2 | .  39 . |
| 4  2  . | 6  1  89| 7  5  38|
+---------+---------+---------+
| 3  .  2 | 5  .  7 | .  1  . |
| 68 .  7 | 1  2  89| .  39 5 |
| 9  15 15| 3  68 4 | 2  7  68|
+---------+---------+---------+

The solved cells are the same, the XY-wing that eliminates <9> in R5C5 is very obvious, and the puzzle is solved.

I prefer to go from Grid 2 to Grid 1 if necessary. If you prefer to simplify Grid 1, that's personal choice.

But, here, the two-candidate cells are all that is needed. I prefer to do only the two-candidate cells first; then, if need be, the three-candidate cells.

Keith
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