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July 29 VH

 
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Earl



Joined: 30 May 2007
Posts: 677
Location: Victoria, KS

PostPosted: Sun Jul 29, 2007 5:16 pm    Post subject: July 29 VH Reply with quote

I got his far and I know that R3C6 should be a 5, but I dont know why?


Code:

+------------+-------------+------------+
| 8   6   24 | 2459 3  1   | 7  25 249  |
| 1   235 7  | 2459 29 8   | 45 6  2349 |
| 245 35  9  | 6    7  25  | 1  8  234  |
+------------+-------------+------------+
| 69  29  8  | 7    5  4   | 3  1  26   |
| 3   4   5  | 1    26 26  | 8  9  7    |
| 67  27  1  | 3    8  9   | 45 25 246  |
+------------+-------------+------------+
| 25  1   6  | 25   4  7   | 9  3  8    |
| 45  8   34 | 59   69 356 | 2  7  1    |
| 79  79  23 | 8    1  23  | 6  4  5    |
+------------+-------------+------------+

Play this puzzle online at the Daily Sudoku site
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Johan



Joined: 25 Jun 2007
Posts: 206
Location: Bornem Belgium

PostPosted: Sun Jul 29, 2007 5:51 pm    Post subject: 29 JYLY VH Reply with quote

Earl,

There is a naked triple in C2, that takes you further on the track for solving the puzzle.
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Earl



Joined: 30 May 2007
Posts: 677
Location: Victoria, KS

PostPosted: Sun Jul 29, 2007 9:54 pm    Post subject: VH July 29 Reply with quote

Johan,

Thanks. I must have had a senior moment to miss the naked pair in box 1. After that, an x-y wing, centered in box 1, eliminates the 5 in R8C6, making R3C6 5, and the puzzle opens up.

Not really a VH, if I had been alert.

Thanks

Earl
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cgordon



Joined: 04 May 2007
Posts: 769
Location: ontario, canada

PostPosted: Mon Jul 30, 2007 1:39 pm    Post subject: Reply with quote

I needed two xy wings: 1) 25 pivot R7C1 and 2) 42 pivot R3C1. Plus a slew of naked triples and pairs and x-wings (particularly on 6's). Maybe there was an easier way. In any event, I enjoyed this one.
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George Woods



Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK

PostPosted: Tue Jul 31, 2007 3:07 pm    Post subject: an intersting (to me) XY chain Reply with quote

Although there are a couple of XY wings that open up the puzzle, I found an alternative route via the pair of 24 in Box 1 along with the pair of 23 in row 9. Usually these simple pairs seem sterile, and hardly worth considering BUT they form a neat XY chain 24 42 23 32 that eliminates the 2 in r3c6 and so to an easy solution
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Jeff



Joined: 06 May 2007
Posts: 46

PostPosted: Tue Jul 31, 2007 8:04 pm    Post subject: July 29 VH Reply with quote

I have read all the various notes above on this puzzle. I cannot seem to find out how to get down to the numbers that appeared in the diagram at the start of the discussion, mainly the pair of 35's in Box 4 and the 3,5's in Box 7. I would appreciate some good input. Many thanks,
Code:

+------------+-------------+------------+
| 8   6  23  | 459  3  1   | 7  25 249  |
| 1   35 7   | 2459 29 8   | 45 6  2349 |
| 24  35 9   | 6    7  25  | 1  8  234  |
+------------+-------------+------------+
| 69  29 8   | 7    5  4   | 3  1  26   |
| 35  4  35  | 1    26 26  | 8  9  7    |
| 67  27 1   | 3    8  9   | 45 25 246  |
+------------+-------------+------------+
| 25  1  6   | 25   4  7   | 9  3  8    |
| 345 8  345 | 59   69 356 | 2  7  1    |
| 79  79 23  | 8    1  23  | 6  4  5    |
+------------+-------------+------------+
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cgordon



Joined: 04 May 2007
Posts: 769
Location: ontario, canada

PostPosted: Tue Jul 31, 2007 8:42 pm    Post subject: Reply with quote

Quote:
I cannot seem to find out how to get down to the numbers that appeared in the diagram at the start of the discussion, mainly the pair of 35's in Box 4


I used an xy wing. The 25 in R7C1 is the pivot cell that "sees" 2 wing cells - the 35 in R5C1 and the 23 in R9C3. The leftover digit in the wing cells (the one not shared with the pivot cell) is a 3. Any cell that "sees" both wing cells cannot contain a 3. Therefore in this case the 3 in R5C3 can be eliminated.
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Johan



Joined: 25 Jun 2007
Posts: 206
Location: Bornem Belgium

PostPosted: Tue Jul 31, 2007 9:18 pm    Post subject: Pair of 35's Reply with quote

Jeff,

I've used an XY-chain length 5 to clear up the [35] pair in box 4.

Starting with number 2[A] in R7C1 => [B]R3C1=4 => [C]R1C3=2 => [D]R9C3=3 => [E]R5C3=5, which eliminates <5> in R5C1 and R8C3.

Code:

[code]
+---------+-------+-------+
| .  . C24| . . . | . . . |
| .  . .  | . . . | . . . |
|B24 . .  | . . . | . . . |
+---------+-------+-------+
| .  . .  | . . . | . . . |
| 3-5. E35| . . . | . . . |
| .  . .  | . . . | . . . |
+---------+-------+-------+
|A25 . .  | . . . | . . . |
| .  .34-5| . . . | . . . |
| .  . D23| . . . | . . . |
+---------+-------+-------+
[/code]
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Jeff



Joined: 06 May 2007
Posts: 46

PostPosted: Tue Jul 31, 2007 9:55 pm    Post subject: July 29 VH Reply with quote

Thanks for the info on cleaning up the 35's in Columns 1 and 3. Now I am looking at Johon's note early in this thread. He indicates that there is an x-y wing "centered in Box 1". I can't figure out which xy wing eliminates the 5 from R8C6. Could you tell me which specific 3 cells are involved. Many thanks,
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Johan



Joined: 25 Jun 2007
Posts: 206
Location: Bornem Belgium

PostPosted: Tue Jul 31, 2007 10:56 pm    Post subject: Reply with quote

Jeff,

Like Earl first replied, there is an xy-wing centered in box1.
The pivot cell [24] is in R3C1. The pincer cells are R3C6[25] and R8C1[45]




Code:

+--------+---------+-------+
| .  . . | . . .   | . . . |
| .  . . | . . .   | . . . |
| 24 . . | . . 25  | . . . |
+--------+---------+-------+
| .  . . | . . .   | . . . |
| .  . . | . . .   | . . . |
| .  . . | . . .   | . . . |
+--------+---------+-------+
| .  . . | . . .   | . . . |
| 45 . . | . . 3-56| . . . |
| .  . . | . . .   | . . . |
+--------+---------+-------+
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Jeff



Joined: 06 May 2007
Posts: 46

PostPosted: Tue Jul 31, 2007 11:55 pm    Post subject: July 29 VH Reply with quote

Johan,

Many thanks. I was under the impression that with those 3 cells, one would call the (45) in C1R8 the Pincer. Is that correct?

Jeff
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Jeff



Joined: 06 May 2007
Posts: 46

PostPosted: Tue Jul 31, 2007 11:56 pm    Post subject: July 29 VH Reply with quote

Whoops. I meant to say that I thought the (45) would be the pivot.

Jeff
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TKiel



Joined: 22 Feb 2006
Posts: 292
Location: Kalamazoo, MI

PostPosted: Wed Aug 01, 2007 11:40 am    Post subject: Reply with quote

The pivot has to share a row/box/column with each pincer.
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