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April 26 DB

 
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Earl



Joined: 30 May 2007
Posts: 677
Location: Victoria, KS

PostPosted: Sat Apr 26, 2008 1:58 pm    Post subject: April 26 DB Reply with quote

The April 26 DB collapses under a (76) w-wing.


Earl

Code:

+-------+-------+-------+
| . . . | . . . | 5 7 . |
| . . . | . . 7 | . . 9 |
| 9 . . | . 2 . | 1 . 3 |
+-------+-------+-------+
| . . 1 | 2 . . | . 3 . |
| 6 4 . | . . . | . 5 7 |
| . 3 . | . . 6 | 9 . . |
+-------+-------+-------+
| 8 . 2 | . 3 . | . . 4 |
| 1 . . | 8 . . | . . . |
| . 6 5 | . . . | . . . |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Sat Apr 26, 2008 8:36 pm    Post subject: Reply with quote



m-wing

{6,7} in r7c7, r8c5

removes 7 in r9c7
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sheryl



Joined: 24 Sep 2007
Posts: 64
Location: New York

PostPosted: Sun Apr 27, 2008 10:47 pm    Post subject: Reply with quote

i love the m-wing diagram, but i don't understand the logic. is there anyway you can explain it, please. Laughing
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Sun Apr 27, 2008 11:00 pm    Post subject: Reply with quote

certainly,

first of all, you need the pair {6,7} to exist.

in this case of the M-wing, we are going to let the 6's be our strong links.

then you might want to read this thread...
http://www.dailysudoku.co.uk/sudoku/forums/viewtopic.php?t=2143.

xy=x=xy=y

67=6=67=7

the {6,7} pair is connected through two stong links on 6, you can see the connection via the red lines in the image in my post.

what you need to make the elimination is a strong link on 7 from the second {6,7} pair. in my image its the green line. that is the strong link on 7.

the combination of these strong links eliminate any 7's that the 7 in r7c7 amd r9c5 see.

or,

if r7c7 is not a 7, then r7c7 must be a 6,
which means r7c4 can't be a 6
which means r8c5 must be a 6
which means r8c5 can't be a 7
which means r9c5 has to be a 7
which means r9c7 can't be a 7 .... that is one direction...

then go the other direction...

if r9c5 is not a 7, then r8c5 has to be a 7
which means, r8c5 can't be a 6
which means, r7c4 has to be a 6
which means, r7c6 can't be a 6
which means, r7c6 has to be a 7
which means r9c7 can't be a 7... other direction...

in either direction, r9c7 can't be a 7
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Asellus



Joined: 05 Jun 2007
Posts: 865
Location: Sonoma County, CA, USA

PostPosted: Sun Apr 27, 2008 11:28 pm    Post subject: Reply with quote

Actually, storm_norm, due to the <7> strong link in r9 that "sees" both of the {67} complementary bivalues, we can go further: those two complementary {67} bivalues must both be <6>. They can't both be <7> else there are no <7>s in r9.

Or, based on that r9 link, the {67} pair is a W-Wing that eliminates <6>(as suggested by Earl), and immediately causes the pair to colapse into <6>s.

Take-home lesson: A W-Wing in a complementary pair immediately collapses into the digit opposite that of the external strong link. The complementary pair means "both are <6> or both are <7>." The W-Wing with external <7> link means "one or both must be <6>." There is only one way out of this: both are <6>.

Or, in keeping with the M-Wing name, we can consult Medusa and she will give us a Wrap:
56  3   15 |#67 

8 67 24 | 367
49 79 12 |#37

We can't have two red <7>s in the same box or column. So, all the reds are false and all the greens are true.
[Edit to clean up line spacing.]
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Sun Apr 27, 2008 11:43 pm    Post subject: Reply with quote

thanx Asellus, I was thinking about using medusa to explain it.

this was weird that an m-wing and a w-wing exist on the same pairs.
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