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July 2 VH

 
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Wed Jul 02, 2008 4:33 am    Post subject: July 2 VH Reply with quote

(Subject edited for correct date - keith)

This was definitely a change of pace from the last one. My solution was:

1) Five ERs

2) M-Wing with pincer extension

3) XY-Wing Chain (some call it an extended XY-Wing) with pincer coloring

Maybe there was one X-Wing which could have killed it off, but I don't look for them except as a last resort.
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Asellus



Joined: 05 Jun 2007
Posts: 865
Location: Sonoma County, CA, USA

PostPosted: Wed Jul 02, 2008 8:49 am    Post subject: Reply with quote

I believe you mean "July 2".

I try to stick with the 3 VH techniques on these... to make it a challenge. I used 2 X-Wings then an XY Wing.
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cgordon



Joined: 04 May 2007
Posts: 769
Location: ontario, canada

PostPosted: Wed Jul 02, 2008 12:08 pm    Post subject: Reply with quote

Something must be wrong when I come up with the least number of solutions.

But anyway: I found a very destructive x-wing on<6> that left an xy-wing on <146>.
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills

PostPosted: Wed Jul 02, 2008 12:18 pm    Post subject: Reply with quote

For me it was also the x-wing on <6> that opened the xy-wing on <146>.

Ted
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George Woods



Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK

PostPosted: Wed Jul 02, 2008 12:19 pm    Post subject: Another maverik solution Reply with quote

Code:

+---------------+-----------------+--------------+
| 25   6   4    | 9     15   3    | 7   125   8  |
| 7    1   58   | 2     4    568  | 9   56    3  |
| 3    9   258  | 7     1568 1568 | 146 12456 46 |
+---------------+-----------------+--------------+
| 8    3   16   | 14    2    7    | 5   46    9  |
| 146  5   9    | 1348  1368 1468 | 2   7     46 |
| 246  24  7    | 45    9    456  | 3   8     1  |
+---------------+-----------------+--------------+
| 9    48  1568 | 13458 1358 2    | 146 146   7  |
| 1246 248 1268 | 148   7    9    | 146 3     5  |
| 145  7   3    | 6     15   145  | 8   9     2  |
+---------------+-----------------+--------------+

Play this puzzle online at the Daily Sudoku site

On this position (straight from draw play without simplification of some of the pencil marks) I became besotted by the 1 4 and 6 in row 4, and row 5 of boxes 4 and 6. Surely there must be a wing of some sort here. NO! couldn't find it BUT it became apparent that whatever the position of the 6 in box 6, the only position left for 6 in box 5 is r6c6.

So no wing was found but the solution came from 2 "almost wings"interacting!! or is this a fanciful conclusion?
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nataraj



Joined: 03 Aug 2007
Posts: 1048
Location: near Vienna, Austria

PostPosted: Wed Jul 02, 2008 5:33 pm    Post subject: Reply with quote

Yellow is the color of my true love's hair...

And 6 is the number. Plus the xy-wing afterwards.


There is also a jellyfish (a rare species: 5 in rows 2,3,6,7 is confined to columns 3,4,6,8 ) that removes 5 from r9c6 and r1c8. That does not solve the puzzle, unfortunately. But 5 comes before 6 and today I checked them in sequence 1,2,3 ...

Code:


+--------------------------+--------------------------+--------------------------+
| 25      6       4        | 9       15      3        | 7       125     8        |
| 7       1       58       | 2       4       568      | 9       56      3        |
| 3       9       258      | 7       68      1568     | 146     12456   46       |
+--------------------------+--------------------------+--------------------------+
| 8       3       16       | 14      2       7        | 5       46      9        |
| 146     5       9        | 1348    368     1468     | 2       7       46       |
| 246     24      7        | 45      9       456      | 3       8       1        |
+--------------------------+--------------------------+--------------------------+
| 9       48      156      | 13458   38      2        | 146     146     7        |
| 1246    248     126      | 148     7       9        | 146     3       5        |
| 145     7       3        | 6       15      145      | 8       9       2        |
+--------------------------+--------------------------+--------------------------+ 
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Wed Jul 02, 2008 5:48 pm    Post subject: Reply with quote

Quote:
Yellow is the color of my true love's hair...

In my house it changes at unpredictable intervals.
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Clement



Joined: 24 Apr 2006
Posts: 1110
Location: Dar es Salaam Tanzania

PostPosted: Wed Jul 02, 2008 6:39 pm    Post subject: Daily Sudoku: Wed 2 Jul-2008 VH Reply with quote

I dont know whether I have grasped the BUG principle. This time again it solved the puzzle quite easily. This how it goes: 5 appears THREE TIMES in row 2 {58, 568, 56} and resides in a three candidate cell r2c6(568), the other undecided cells r2c3 & r2c8 have TWO candidates. Accordingly 5 goes in r2c6 solving the puzzle. Is that true? How can this be explained/proved?
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storm_norm



Joined: 18 Oct 2007
Posts: 1741

PostPosted: Wed Jul 02, 2008 6:50 pm    Post subject: Reply with quote

using the draw play, I found the x-wing on 5 first, probably didn't have all the basics done to that point. but it took a while to see all the eliminations from the 6 x-wing.
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wapati



Joined: 10 Jun 2008
Posts: 472
Location: Brampton, Ontario, Canada.

PostPosted: Wed Jul 02, 2008 7:32 pm    Post subject: Re: Daily Sudoku: Wed 2 Jul-2008 VH Reply with quote

Clement wrote:
I dont know whether I have grasped the BUG principle. This time again it solved the puzzle quite easily. This how it goes: 5 appears THREE TIMES in row 2 {58, 568, 56} and resides in a three candidate cell r2c6(568), the other undecided cells r2c3 & r2c8 have TWO candidates. Accordingly 5 goes in r2c6 solving the puzzle. Is that true? How can this be explained/proved?


This is not a BUG+1 because there are many cells left with 3 or more candidates. You don't get to use it just because a row or column has only one triple candidate cell. Sorry! Crying or Very sad
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nataraj



Joined: 03 Aug 2007
Posts: 1048
Location: near Vienna, Austria

PostPosted: Wed Jul 02, 2008 8:25 pm    Post subject: Re: Daily Sudoku: Wed 2 Jul-2008 VH Reply with quote

Clement wrote:
I dont know whether I have grasped the BUG principle. This time again it solved the puzzle quite easily. This how it goes: 5 appears THREE TIMES in row 2 {58, 568, 56} and resides in a three candidate cell r2c6(568), the other undecided cells r2c3 & r2c8 have TWO candidates. Accordingly 5 goes in r2c6 solving the puzzle. Is that true? How can this be explained/proved?


It cannot.

In row one, there are three cells with candidate "5". Two of them have two candidates, only r1c8 has three candidates. But it is not "5" that solves cell r1c8, it is "1".

Quote:
This time again it solved the puzzle quite easily


"Luck"?

You have NOT grasped the BUG priciple. You will if you read up on it ... Smile

http://www.sudopedia.org/wiki/BUG
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Asellus



Joined: 05 Jun 2007
Posts: 865
Location: Sonoma County, CA, USA

PostPosted: Wed Jul 02, 2008 10:15 pm    Post subject: Reply with quote

George Woods wrote:
On this position (straight from draw play without simplification of some of the pencil marks) I became besotted by the 1 4 and 6 in row 4, and row 5 of boxes 4 and 6. Surely there must be a wing of some sort here. NO! couldn't find it BUT it became apparent that whatever the position of the 6 in box 6, the only position left for 6 in box 5 is r6c6.

There is a way to see this. But first, your description doesn't work for me. The <6> at r6c6 can "see" the <6> at r4c8 via the ERs in boxes 2 and 3. So, it cannot be true if r4c8 is true.

However, if you consider the otherwise useless XYZ-Wing at r4c3|r5c19, one of those 3 cells must be <6>. The two in b4 can be transported to r6c6, as can the one in r5c9. Thus, r6c6 must be <6> due to the XYZ-Wing.
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Asellus



Joined: 05 Jun 2007
Posts: 865
Location: Sonoma County, CA, USA

PostPosted: Wed Jul 02, 2008 10:26 pm    Post subject: Reply with quote

nataraj,

Regarding Jellyfish, they really aren't all that rare. It's just that we usually notice the smaller complementary fish instead. As Myth Jellies has pointed out, your basic fish are constraint sets. And, they always occur in complementary groups of two or more. You might have a Swordfish and a Jellyfish together, or a Swordfish and two X-Wings, for instance. What is rare is two complementary Jellyfish (or a Jellyfish and a "5-Fish").

In this puzzle, I noticed the complementary X-Wing in c15 rather than the Jellyfish. And, like you I started with the lower numbers in sequence so found the (apparently unneeded) 5 X-Wing before the more useful 6 X-Wing.
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nataraj



Joined: 03 Aug 2007
Posts: 1048
Location: near Vienna, Austria

PostPosted: Thu Jul 03, 2008 6:42 am    Post subject: Reply with quote

Thanks, Asellus, for the explanation.
Funny I should have seen that complex jellyfish and not seen the simple x-wing. Must have looked at the grid cross-eyed. I'll close one eye from now on to safeguard against such lapses Wink
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George Woods



Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK

PostPosted: Sat Jul 05, 2008 5:54 pm    Post subject: Reply with quote

Asellus wrote:
George Woods wrote:
On this position (straight from draw play without simplification of some of the pencil marks) I became besotted by the 1 4 and 6 in row 4, and row 5 of boxes 4 and 6. Surely there must be a wing of some sort here. NO! couldn't find it BUT it became apparent that whatever the position of the 6 in box 6, the only position left for 6 in box 5 is r6c6.

There is a way to see this. But first, your description doesn't work for me. The <6> at r6c6 can "see" the <6> at r4c8 via the ERs in boxes 2 and 3. So, it cannot be true if r4c8 is true.

However, if you consider the otherwise useless XYZ-Wing at r4c3|r5c19, one of those 3 cells must be <6>. The two in b4 can be transported to r6c6, as can the one in r5c9. Thus, r6c6 must be <6> due to the XYZ-Wing.


"My description didn't work for you!. " Whichever 6 is chosen in box 6 solves the whole of row 5 and row 6 of box 4, and both possibilities put a 6 on both rows 4 and 5 (rather like an X wing) So the 6 in box 5 falls out as does the puzzle!
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