dailysudoku.com

prakash · Joined: 02 Jan 2008 Posts: 67 Location: New Jersey, USA

than this have severely reduced fitness faster rates of cell growth and cell pro- changes in antigenic and cytoadherent
give in to it! Better to give in to a craving and allow yourself 100 extra calories broom handles, and balls of various assimilate inorganic minerals. You can only assimilate
Yeah, sorry for the views with no responses. I tend to stay away from NetBeans, after having used it years ago when it really wasn't all that good. Eclipse is where it's at for me, though I'm sure
gous, leading to the suggestion that the unit, units with D- and L-configurations590 Chirality in Biology morphology. The fact that cells commonly

storm_norm · Joined: 18 Oct 2007 Posts: 1741

nataraj · Posted: Wed Aug 06, 2008 6:08 am Post subject:

Same solution as prakash.

The xy becomes visible only after the x.
Here's the position after basics

Captain Pete · Joined: 09 Jun 2007 Posts: 55 Location: Oley, PA

I an not an "advanced" puzzle solver, but after doing VH puzzles at this site for a year or so, they are no longer much of a challenge. After basics on today's puzzle, one obvious XYZ wing opened up the puzzle to a quick solution. I wonder if the folks running this site couldn't include a "super hard" from time to time, along the lines of the SH Menneske puzzles. Not only would the puzzles be a challenge, the discussion would be helpful to those of us trying to learn advanced techniques.

wings · Joined: 06 Aug 2008 Posts: 1 Location: HONG KONG

Marty R. · Posted: Wed Aug 06, 2008 3:35 pm Post subject:

The one XYZ-Wing 168-18-16 pivoted in r3c1 was my only move.

Clement · Posted: Wed Aug 06, 2008 6:57 pm Post subject: Daily Sudoku: Wed 6-Aug-2008 VH

There is a potential deadly pattern on {1/6} in r23c14. 8 cannot be a candidate in r3c7 as it leads to a deadly pattern in r23c14. Therefore, 8 must be in r1c9. This solves the puzzle Smile

.

nataraj

Florida Bob · Joined: 25 Jul 2007 Posts: 12

I didn't find any wings however I found that if R3C2 is a 1 then you have a bug situation. Place the 9 there and the puzzle solves quickly.

nataraj · Posted: Wed Aug 06, 2008 8:03 pm Post subject:

Clement · Posted: Wed Aug 06, 2008 8:23 pm Post subject: Daily Sudoku: Wed 6-Aug-2008 VH

It goes like this:r3c7=8 leaves {1/6} in r3c1 and r1c9=1, r2c7=7,r2c3=2 leaving {1/6} in r2c1 the deadly pattern.

nataraj · Posted: Wed Aug 06, 2008 8:56 pm Post subject:

I see ... From r1c9=1 we get
a) (by way of c9, r9, c1 and r1; my chain) r3c1=6 and r2c1=2
b) (by way of r1 and r2; Clement's chain) r2c1<>2

So, with or without the uniqueness argument, 1 in r1c9 is toast...

Asellus · Posted: Wed Aug 06, 2008 9:56 pm Post subject:

Clement's elimination is an XY Chain that exploits the strong link (2=8) induced in the 16 UR:
UR[(8)r3c1=(2)r2c1] - (2=7)r2c3 - (7=1)r2c7 - (1=8)r1c9; r3c7<>8

arkietech · Posted: Wed Aug 06, 2008 10:56 pm Post subject:

A couple of x-wings and a triple got me here:

kragzy · Joined: 01 May 2007 Posts: 112 Location: Australia

I'm with arkitech on this one. Basics led me to the position posted by him and all that I could see was the BUG which solved it quickly. Being a disliker of uniqueness solutions, I looked for a wing but couldn't find any. Obviously didn't check carefully enough.

To save me the effort of re-looking, can you tell where you saw the XY wing please Dan.

Thanks

kragzy · Joined: 01 May 2007 Posts: 112 Location: Australia

Oh, and I meant to say, welcome to the forum!

Cheers

Marty R. · Posted: Thu Aug 07, 2008 3:35 am Post subject:

kragzy · Joined: 01 May 2007 Posts: 112 Location: Australia

Ah-ha! I knew it would be there somewhere.

Thanks Marty-Dan

arkietech · Posted: Thu Aug 07, 2008 10:53 am Post subject:

kragzy said:

kragzy · Joined: 01 May 2007 Posts: 112 Location: Australia

thanks