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storm_norm
Joined: 18 Oct 2007
Posts: 1741
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 Posted: Mon Sep 07, 2009 4:51 pm Post subject: MM 1517 & 1519 |
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#1517
| Code: |
+-------+-------+-------+
| . . . | . . . | . . . |
| . . 2 | . . 5 | 7 8 . |
| 6 . . | 8 . 3 | . . 5 |
+-------+-------+-------+
| 4 . 6 | . . . | . . 7 |
| . 1 . | 6 8 2 | . 4 . |
| 2 . . | . . . | 1 . 9 |
+-------+-------+-------+
| . . . | 9 . 7 | . . . |
| . 3 5 | 4 . . | 6 . . |
| . . . | . . . | . . . |
+-------+-------+-------+
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open in draw/play
#1519 | Code: |
+-------+-------+-------+
| . 5 . | . 6 . | . . 2 |
| . . . | . . 9 | 3 . . |
| . 4 . | 1 . . | . 7 . |
+-------+-------+-------+
| . . . | . . . | 2 . 5 |
| . . 1 | 3 . . | 8 . 6 |
| 8 . 2 | . . . | . . . |
+-------+-------+-------+
| . . . | . . 1 | . 9 . |
| 1 . 7 | 6 . . | . . . |
| 4 . . | . 2 . | . 5 . |
+-------+-------+-------+
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open in draw/play |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Tue Sep 08, 2009 1:54 pm Post subject: |
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For #1517, a two step sequence did the deed. | Quote: | ER 2 with hinge in box2 and strong link in row8,
xy-wing 1-68 with vertex18 in r8c6 and extended pincer 16: (1)r8c6 - (1=2)r8c5 - (2)r8c9 = (2)r7c9 - (2=6)r7c2; r9c2<>6.
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Ted |
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tlanglet
Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
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| Posted: Tue Sep 08, 2009 4:52 pm Post subject: |
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My first attempt at MM 1519 was essentially useless; a single x-wing that led nowhere. I hope to try again later.
Ted |
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daj95376
Joined: 23 Aug 2008
Posts: 3854
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| Posted: Tue Sep 08, 2009 5:48 pm Post subject: |
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[Withdrawn: nothing of real value.]
Last edited by daj95376 on Wed Sep 09, 2009 4:46 am; edited 1 time in total |
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keith
Joined: 19 Sep 2005
Posts: 3355
Location: near Detroit, Michigan, USA
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| Posted: Tue Sep 08, 2009 8:19 pm Post subject: |
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1517: After a skyscraper on 2: | Code: | +-------------------+-------------------+-------------------+
| 5 479 8 | 27 24679 69 | 24 3 1 |
| 3 49 2 | 1 49 5 | 7 8 6 |
| 6 47 1 | 8 247 3 | 24 9 5 |
+-------------------+-------------------+-------------------+
| 4 5 6 | 3 19 19 | 8 2 7 |
| 7 1 9 | 6 8 2 | 5 4 3 |
| 2 8 3 | 57 57 4 | 1 6 9 |
+-------------------+-------------------+-------------------+
| 18 2r6g 4 | 9 256 7 | 3 15 2r8g |
| 9 3 5 | 4 12 18g | 6 7 28r |
| 18 26r 7 | 25 3 6g8r | 9 15 4 |
+-------------------+-------------------+-------------------+ |
Medusa coloring gives two 2r in R7, so g must be true.
Also, there is a 4-cell chain 26 - 68 - 18 - 12 that takes out 2 in R9C4.
Keith |
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storm_norm
Joined: 18 Oct 2007
Posts: 1741
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| Posted: Thu Sep 10, 2009 3:53 am Post subject: |
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#1519
| Code: | .------------------.------------------.------------------.
| 39 5 39 | 47 6 47 | 1 8 2 |
| 7 1 8 | 2 5 9 | 3 6 4 |
| 2 4 6 | 1 38 38 | 5 7 9 |
:------------------+------------------+------------------:
| 369 3679 4 | 789 1789 678 | 2 13 5 |
| 5 79 1 | 3 79 2 | 8 4 6 |
| 8 36 2 | 5 14 46 | 9 13 7 |
:------------------+------------------+------------------:
| 36 2 5 | 478 3478 1 | 67 9 38 |
| 1 389 7 | 6 389 5 | 4 2 38 |
| 4 3689 39 | 789 2 378 | 67 5 1 |
'------------------'------------------'------------------' |
1...(7=6)r7c7 - (6)r7c1 = (6-9)r4c1 = (9)r45c2 - (9)r8c2 = (9)r8c5 - (9=7)r5c5; r7c5 <> 7....
locked 7's in box 5
2...(7)r9c6 = (7-4)r1c6 = (4-6)r6c6 = (6)r6c2 - (6)r9c2 = (6)r9c7; r9c7 <> 7... couple singles
3...(8=4)r7c4 - (4)r1c4 = (4)r1c6 - (4=6)r6c6 - (6=8)r4c6; r4c4 <> 8
singles to the end.
Last edited by storm_norm on Thu Sep 10, 2009 6:10 pm; edited 1 time in total |
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Myth Jellies
Joined: 27 Jun 2006
Posts: 64
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| Posted: Thu Sep 10, 2009 5:08 pm Post subject: |
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| keith wrote: | 1517: After a skyscraper on 2: | Code: | +-------------------+--------------------+-------------------+
| 5 *479 8 | 27 *479+26 69 | 24 3 1 |
| 3 *49 2 | 1 *49 5 | 7 8 6 |
| 6 *47 1 | 8 *47+2 3 | 24 9 5 |
+-------------------+--------------------+-------------------+
| 4 5 6 | 3 19 19 | 8 2 7 |
| 7 1 9 | 6 8 2 | 5 4 3 |
| 2 8 3 | 57 57 4 | 1 6 9 |
+-------------------+--------------------+-------------------+
| 18 26 4 | 9 &256 7 | 3 15 28 |
| 9 3 5 | 4 1-2 18 | 6 7 28 |
| 18 26 7 |&25 3 68 | 9 15 4 |
+-------------------+--------------------+-------------------+ |
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Also there is the 479-MUG in r123c25 which combines with the 256-ALS in box 8 to form a freaky MUG-assisted quasi-XYZ-wing that eliminates the 2 from r8c5. Here is the AIC
(2)r13c5 =MUG= (6)r1c5 - ALS(6=5&2)r7c5,r9c4 => r8c5 <> 2
Puzzle, you've just been mugged--Mwaah hahaha!
edit - Actually, if you add in cells r13c7, I think you have a 2479-MUG in that top tier that leaves r1c5 = 6 as the only escape. |
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ttt
Joined: 06 Dec 2008
Posts: 42
Location: vietnam
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| Posted: Thu Sep 10, 2009 5:36 pm Post subject: |
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| Myth Jellies wrote: | | keith wrote: | 1517: After a skyscraper on 2: | Code: | +-------------------+--------------------+-------------------+
| 5 *479 8 | 27 *479+26 69 | 24 3 1 |
| 3 *49 2 | 1 *49 5 | 7 8 6 |
| 6 *47 1 | 8 *47+2 3 | 24 9 5 |
+-------------------+--------------------+-------------------+
| 4 5 6 | 3 19 19 | 8 2 7 |
| 7 1 9 | 6 8 2 | 5 4 3 |
| 2 8 3 | 57 57 4 | 1 6 9 |
+-------------------+--------------------+-------------------+
| 18 26 4 | 9 &256 7 | 3 15 28 |
| 9 3 5 | 4 1-2 18 | 6 7 28 |
| 18 26 7 |&25 3 68 | 9 15 4 |
+-------------------+--------------------+-------------------+ |
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Also there is the 479-MUG in r123c25 which combines with the 256-ALS in box 8 to form a freaky MUG-assisted quasi-XYZ-wing that eliminates the 2 from r8c5. Here is the AIC
(2)r13c5 =MUG= (6)r1c5 - ALS(6=5&2)r7c5,r9c4 => r8c5 <> 2 |
Very nice deduction! And it seems that you intend to add some new to your original AIC? Perhaps, it should be… 
ttt |
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storm_norm
Joined: 18 Oct 2007
Posts: 1741
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| Posted: Thu Sep 10, 2009 6:27 pm Post subject: |
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could you also express it like this?
MUG479[(26)r13c5 = (25)r79c45]; r8c5 <> 2 |
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Myth Jellies
Joined: 27 Jun 2006
Posts: 64
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| Posted: Thu Sep 10, 2009 8:21 pm Post subject: |
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| storm_norm wrote: | could you also express it like this?
MUG479[(26)r13c5 = (25)r79c45]; r8c5 <> 2 |
That would be confusing. The MUG only forces either a 2 or a 6, but not necessarily both to be true (just like a UR). Thus you have a strong link between the 2's and the 6 due to the MUG, so you now need a weak link such as the 6 from the ALS to connect to it. Finally you finish it off with the remaining strong link of the ALS subpattern
If I hadn't already shown the MUG in a diagram, I would probably present it as
| Code: |
MUG(479#6)r123c25 (the #6 here implies six instances of the preceding digits)
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(6)r1c5 - (6=5&2)r7c5,r9c4
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(2)r13c5 =====> r8c5 <> 2 |
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