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		| Earl 
 
 
 Joined: 30 May 2007
 Posts: 677
 Location: Victoria, KS
 
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				|  Posted: Sat Oct 17, 2009 2:24 pm    Post subject: Oct 17 DB |   |  
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				| The October 17 DB falls as easily as autumn leaves. 
 Solution  skyscraper (9)
 Earl
 
 
 
  	  | Code: |  	  | +-------+-------+-------+
 | . . 3 | . . . | 4 . 7 |
 | . . 2 | 1 . . | . 5 8 |
 | . . 8 | . 4 6 | . . . |
 +-------+-------+-------+
 | . . . | . 2 7 | 1 . 4 |
 | . . . | . . . | . . . |
 | 2 . 9 | 4 3 . | . . . |
 +-------+-------+-------+
 | . . . | 3 8 . | 9 . . |
 | 7 8 . | . . 9 | 5 . . |
 | 3 . 5 | . . . | 8 . . |
 +-------+-------+-------+
 
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 Play this puzzle online at the Daily Sudoku site
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		| arkietech 
 
 
 Joined: 31 Jul 2008
 Posts: 1834
 Location: Northwest Arkansas USA
 
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				|  Posted: Sat Oct 17, 2009 2:50 pm    Post subject: |   |  
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		| tlanglet 
 
 
 Joined: 17 Oct 2007
 Posts: 2468
 Location: Northern California Foothills
 
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				|  Posted: Sat Oct 17, 2009 11:12 pm    Post subject: |   |  
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				| Continuing my recent interest with UR implications, I used the UR23 in r35c78. To prevent bad things happening, either r9c8=2 or r4c8=3. Using this implication, we get the following AIC: (6=2)r9c9 - UR23[(2)r9c8 = (3)r4c8] - (3=5)r4c2 - (5=1)r6c2 - (1=8)r6c6 - (8=6)r6c8; r6c9<>6
 After clean-up, a BUG+1 forces r3c8=9 to complete the puzzle.
 
 Ted
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