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		sarah Guest
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 4:15 am    Post subject: March 8!!! | 
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				Very strange ... I often solve very hard puzzles, yet this "hard" puzzle has me so stumped I can't get more than 3 numbers filled in!!!  I'm totally puzzled (no pun intended).     
 
 
So far I have 8 in c1r5, 5 in c9r4 and 9 in c3r8.  Draw gives a hint of 8 in c7r9, then 2 in c9r9.  Those hints not only leave me clueless still, but I can't figure out why they make sense.
 
 
Any help?
 
 
Thanks!
 
Sarah | 
			 
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		guest Guest
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 9:54 am    Post subject: Re: March 8!!! | 
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				 	  | sarah wrote: | 	 		  |  ... 5 in c9r4 ... | 	  
 
I dont know how you found this. 
 
Anyway, the key is the naked triplet in box3/column 8. | 
			 
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		George woods Guest
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 11:58 am    Post subject: solving it | 
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				e7b7e98i3h3f4 is how I started
 
 
abc
 
def
 
ghi
 
 
and e7 menas put a 7 into obvious square in block e | 
			 
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		Guest
 
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 12:04 pm    Post subject:  | 
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				George,
 
i suppose you have another puzzle, i was talking about this one (where 7 is a given in block e)
 
 	  | Code: | 	 		  ------------
 
.8.|1..|4..
 
1.7|...|..9
 
...|..6|1.3
 
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7..|..4|.6.
 
...|2.3|...
 
.9.|7..|..8
 
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2.8|5..|...
 
5..|...|7.1
 
..3|..9|.5.
 
------------
 
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		george woods Guest
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 12:10 pm    Post subject:  | 
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				Ok I haven't checked it against original but my record is
 
 
f7d8i8g9i2f5c65
 
 
I have put an exclamation mark beside f7 implying something subtle! | 
			 
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		george woods Guest
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 12:24 pm    Post subject: march 8 | 
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				| The subtelty arises from the pair 56 in Cc and Cg (because of the 5 and 6 in col 8 | 
			 
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		george Guest
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 12:27 pm    Post subject:  | 
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				| I mean of course Cc and Cd | 
			 
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		Guest
 
 
 
 
 
 
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				 Posted: Tue Mar 28, 2006 1:38 pm    Post subject:  | 
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				| Yep, now we are on the same line. The hidden pair 56 in box 3 (c) is the counterpart to the triplet i mentioned. | 
			 
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		TKiel
 
 
  Joined: 22 Feb 2006 Posts: 292 Location: Kalamazoo, MI
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				 Posted: Tue Mar 28, 2006 9:11 pm    Post subject:  | 
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				Sarah,
 
 
  If you've made the exclusions from the naked triple in box 3, then the only possibility in box 9 for an 8 is r9c7, which then makes r9c9 the only possibility for a 2. | 
			 
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		sarah Guest
 
 
 
 
 
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				 Posted: Thu Mar 30, 2006 7:20 pm    Post subject:  | 
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				Tracy- Thank you.  Your response was the only one that made any sense to me.  I do not know what a "naked triplet" is... although I do have the limitations of 27 for c8r1, 28 for c8r2, and 278 for c8r3.  So I see how the 8 must therefore be in c7r9.  But c9r9 can still be a 2 OR a 4, no?
 
 
And what is George going on about?  All his letters and numbers are a mystery to me...
 
 
Sarah | 
			 
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		sarah Guest
 
 
 
 
 
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				 Posted: Thu Mar 30, 2006 7:27 pm    Post subject:  | 
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				I take that back -- I see why c9r9 has to be a 2!
 
Thank you. | 
			 
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		Guest
 
 
 
 
 
 
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				 Posted: Fri Mar 31, 2006 5:17 pm    Post subject:  | 
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				Glad to see a response finally, Sarah, sorry for the "t" in "naked triplet" (i am not English), which seemed to confuse you so, that 
 
- you could not see the triple in the 3 cells i mentioned
 
- not the naked pair i mentioned
 
- and you were not able to ask what i meant with it
 
i will .ry .o avoid .he "t" in the fu.ure   | 
			 
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