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		someone_somewhere
 
 
  Joined: 07 Aug 2005 Posts: 275 Location: Munich
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				 Posted: Sat Apr 01, 2006 4:20 pm    Post subject: it's the 1 april - time of a real challange - Zen Sudoku | 
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				Hi,
 
I know, nobody has yet solved the previous Zen sudoku.
 
Now on the 1. April it's time for an other one.
 
We just take the old (unsolved) one:
 
 	  | Code: | 	 		  6.2.5....
 
.....4.3.
 
.........
 
43...8...
 
.1....2..
 
......7..
 
5..27....
 
.......81
 
...6..... | 	  
 
and swap in row 2 the digits 4 and 3:
 
 
 	  | Code: | 	 		  6.2.5....
 
.....3.4.
 
.........
 
43...8...
 
.1....2..
 
......7..
 
5..27....
 
.......81
 
...6..... | 	  
 
Small change, but the difficulty level is the same.
 
If you find an other one, at this level, please post it, I will be glad to break the rest of my brain cells on it ;-)
 
 
see u, | 
			 
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		ravel Guest
 
 
 
 
 
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				 Posted: Mon Apr 03, 2006 9:59 am    Post subject:  | 
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				This is my solution for the second puzzle. I start from here:
 
 
 	  | Code: | 	 		  6      4789   2       | 14789  5     479    | 1389  179    39         
 
1789   5789   15789   | 1789   169   3      | 1689  4      2          
 
13789  4789   134789  | 14789  1469  2      | 1689  15679  569  
 
----------------------------------------------------------------      
 
4      3      5679    | 1579   2     8      | 169   1569   569        
 
789    1      56789   | 34579  349   45679  | 2     3569   48         
 
289    25689  5689    | 13459  1349  4569   | 7     13569  48     
 
----------------------------------------------------------------    
 
5      4689   134689  | 2      7     149    | 3469  69     369        
 
279    24679  4679    | 3459   349   459    | 4569  8      1          
 
139    49     1349    | 6      8     1459   | 3459  2      7          
 
 | 	  
 
1. If r4c4=7:
 
r1c6=7, r1c2<>7, r3c8=7, r3c2<>7, r3c9=5, triple 489 in r139c2, r7c2=6, r8c7=6
 
no 6 for box 3 left => r4c3=7    
 
 
2. If r7c2=8:
 
pair r68c2=26, r2c2=5, (r1c2|r3c2=7) r23c13<>7, r2c4=7, r5c6=7, r4c3=7, r8c1=7, r8c2=2, r6c2=6 
 
no 6 in column 6 left => r7c3=8 
 
 
This brings me here:
 
 
 	  | Code: | 	 		  6      4789   2       | 14789  5     479    | 1389  179    39         
 
1789   5789   159     | 1789   169   3      | 1689  4      2          
 
13789  4789   1349    | 14789  1469  2      | 1689  15679  569  
 
----------------------------------------------------------------      
 
4      3      7       | 159    2     8      | 169   1569   569        
 
89     1      569     | 34579  349   45679  | 2     3569   48         
 
289    25689  569     | 13459  1349  4569   | 7     13569  48     
 
----------------------------------------------------------------    
 
5      469    8       | 2      7     1      | 3469  69     369        
 
27     27     469     | 3459   349   459    | 4569  8      1          
 
13     49     13      | 6      8     459    | 459   2      7          
 
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If r5c6=6:
 
(a) r6c2=6,r8c2=2, r8c1=7, 
 
(b) r5c4=7, r1c6=7, r3c9=7 r2c2=7
 
no 5 for column 2 => r6c6=6,
 
 
what  finally solves the puzzle,
 
 
ravel | 
			 
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		ravel Guest
 
 
 
 
 
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				 Posted: Mon Apr 03, 2006 1:21 pm    Post subject:  | 
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				Sorry, checking it again, i saw, that i made a mistake, when i tried to simplify the last chain. The right one is:
 
If r5c6=6:
 
r5c4=7, r1c6=7, r3c8=7, r2c2=7,
 
r3c9=5, (r1c7|r2c7|r3c7=6) r8c7<>6, r8c3=6, r6c2=6
 
 
The 3 chains also solve the first puzzle. I noticed, that these "twin sudokus" (2 numbers changed) mostly have very similar solution paths. | 
			 
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		ravel Guest
 
 
 
 
 
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				 Posted: Mon Apr 03, 2006 1:28 pm    Post subject:  | 
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				Darned, still uncomplete  
 
If r5c6=6:
 
r5c4=7, r1c6=7, r3c8=7, r3c9=5, (r1c7|r2c7|r3c7=6) r8c7<>6, r8c3=6, r6c2=6,
 
r6c1=2, r8c1=7, r2c2=7 | 
			 
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