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		Clement
 
 
  Joined: 24 Apr 2006 Posts: 1113 Location: Dar es Salaam Tanzania
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				 Posted: Wed May 29, 2013 10:23 pm    Post subject: May 30 VH | 
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+------------+----------+--------------+
 
| *28  3  24  | 9   1 6  | *58   7   45  |
 
| 1   68 5   | 2   4 7  | 689  6-89 3   |
 
| 9   46 7   | 35  8 35 | 26   126 146 |
 
+------------+----------+--------------+
 
| 4   2  8   | 136 7 13 | 69   5   169 |
 
| 6   5  3   | 14  9 2  | 7    14  8   |
 
| 7   9  1   | 46  5 8  | 3    46  2   |
 
+------------+----------+--------------+
 
| 3   7  69  | 158 2 15 | 4    68-9 #569 |
 
| 25-8 48 246 | 58  3 9  | 1    268 7   |
 
| *258 1  29  | 7   6 4  | *2589 3   59  |
 
+------------+----------+--------------+
 
 | 	  X-Wing on 8 in r19c17; r8c1<>8, r2c7<>8 and
 
XYZ-Wing 569 with apex in r7c9; r7c8<>9; stte. | 
			 
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		arkietech
 
 
  Joined: 31 Jul 2008 Posts: 1834 Location: Northwest Arkansas USA
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				 Posted: Wed May 29, 2013 11:21 pm    Post subject: Re: May 30 VH | 
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				 	  | Clement wrote: | 	 		  X-Wing on 8 in r19c17; r8c1<>8, r2c7<>8 and
 
XYZ-Wing 569 with apex in r7c9; r7c8<>9; stte. | 	  
 
 
All i needed was the x-wing for lclste. | 
			 
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		Marty R.
 
 
  Joined: 12 Feb 2006 Posts: 5770 Location: Rochester, NY, USA
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				 Posted: Thu May 30, 2013 1:26 am    Post subject: Re: May 30 VH | 
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				 	  | arkietech wrote: | 	 		   	  | Clement wrote: | 	 		  X-Wing on 8 in r19c17; r8c1<>8, r2c7<>8 and
 
XYZ-Wing 569 with apex in r7c9; r7c8<>9; stte. | 	  
 
 
All i needed was the x-wing for lclste. | 	  
 
 
The X-Wing did it for me as well. | 
			 
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		hughwill
 
 
  Joined: 05 Apr 2010 Posts: 424 Location: Birmingham UK
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				 Posted: Thu May 30, 2013 10:14 am    Post subject: Re: May 30 VH | 
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				Looks to me as though the X wing on 8 and the XYZ on 569 are both
 
single shots..... | 
			 
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		TerenceF
 
 
  Joined: 21 Dec 2007 Posts: 26 Location: Takapuna, NZ
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				 Posted: Mon Jun 03, 2013 4:59 am    Post subject:  | 
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				As an alternative, from the same starting point, there is an XY chain starting at r1c9 which eliminates the 5 from r7c9 thus:
 
 
If r1c9 = 5 then r7c9<>5 AND
 
If r1c9 = 4 then r1c3=2 so r9c3=9 so r9c9=5 so r7c9<>5
 
 
THis forces r7c8 = 8 which solves the puzzle. | 
			 
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