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a puzzle from brainbashers

 
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George Woods



Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK

PostPosted: Mon Dec 22, 2014 3:03 pm    Post subject: a puzzle from brainbashers Reply with quote

Code:

+--------------+---------------+-----------+
| 3   58   6   | 258  7    1   | 4  258 9  |
| 589 4589 7   | 2358 4568 346 | 1  258 26 |
| 1   2    458 | 58   4568 9   | 68 7   3  |
+--------------+---------------+-----------+
| 589 3    58  | 7    1    2   | 68 489 46 |
| 4   7    2   | 6    9    8   | 5  3   1  |
| 689 689  1   | 4    3    5   | 2  89  7  |
+--------------+---------------+-----------+
| 2   1    45  | 9    45   7   | 3  6   8  |
| 568 4568 9   | 1358 4568 346 | 7  124 24 |
| 7   468  3   | 18   2    46  | 9  14  5  |
+--------------+---------------+-----------+

Play this puzzle online at the Daily Sudoku site

This is a partially solved puzzle from brainbashers. As it is Draw/Play grades it very hard but can solve it with three "advanced" moves I agree with them all , but cannot see the "rules" used
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Mon Dec 22, 2014 4:25 pm    Post subject: Reply with quote

George, I'd have a much easier time trying this if you'd post the original puzzle.
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA

PostPosted: Mon Dec 22, 2014 7:43 pm    Post subject: Reply with quote

George -- a good one Very Happy

Code:
 *-----------------------------------------------------------*
 | 3     58    6     | 258   7     1     | 4     258   9     |
 |a589  b4589  7     | 2358  4568  346   | 1     258   26    |
 | 1     2    c458   | 58    4568  9     | 68    7     3     |
 |-------------------+-------------------+-------------------|
 |e58-9  3    d58    | 7     1     2     | 68    489   46    |
 | 4     7     2     | 6     9     8     | 5     3     1     |
 | 689   689   1     | 4     3     5     | 2     89    7     |
 |-------------------+-------------------+-------------------|
 | 2     1     45    | 9     45    7     | 3     6     8     |
 | 568   4568  9     | 1358  4568  346   | 7     124   24    |
 | 7     468   3     | 18    2     46    | 9     14    5     |
 *-----------------------------------------------------------*
9r2c1=(9-4)r2c2=(4-8)r3c3=(8-5)r4c3=5r4c1 => -9r4c1; ste
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George Woods



Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK

PostPosted: Mon Dec 22, 2014 10:26 pm    Post subject: original puzzle Reply with quote

Code:

+-------+-------+-------+
| 3 . 6 | . 7 . | 4 . 9 |
| . . 7 | . . . | 1 . . |
| 1 2 . | . . . | . 7 3 |
+-------+-------+-------+
| . . . | 7 1 2 | . . . |
| 4 . . | 6 . 8 | . . 1 |
| . . . | 4 3 5 | . . . |
+-------+-------+-------+
| 2 1 . | . . . | . 6 8 |
| . . 9 | . . . | 7 . . |
| 7 . 3 | . 2 . | 9 . 5 |
+-------+-------+-------+

Play this puzzle online at the Daily Sudoku site
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Tue Dec 23, 2014 1:37 am    Post subject: Reply with quote

I used four moves, X-Wings on 8 and 4 and XY-Wings on 68-2 and 48-5.

George, I don't understand this sentence: "As it is Draw/Play grades it very hard but can solve it with three "advanced" moves I agree with them all , but cannot see the "rules" used"
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George Woods



Joined: 28 Mar 2006
Posts: 304
Location: Dorset UK

PostPosted: Tue Dec 23, 2014 9:15 am    Post subject: notation help please Reply with quote

Arkietech gave a solution
9r2c1=(9-4)r2c2=(4-8)r3c3=(8-5)r4c3=5r4c1 => -9r4c1; ste

I thought I Understood the notation but I need a primer on it. Can anyone help?
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Tue Dec 23, 2014 12:35 pm    Post subject: Re: notation help please Reply with quote

George Woods wrote:
Arkietech gave a solution
9r2c1=(9-4)r2c2=(4-8)r3c3=(8-5)r4c3=5r4c1 => -9r4c1; ste

I thought I Understood the notation but I need a primer on it. Can anyone help?


If r2c1 is not 9, then r2c2 is a 9 and if that cell is not 4, then r3c3 is a 4 and if it's not an 8 then r4c3 is an 8 and if it's not 5 then r4c1 is a 5.

To summarize, If r2c1 is not a 9, then r4c1 is a 5. if r2 c1 is a 9 then r4c1 cannot be=9.

Hope that helps.
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