| View previous topic :: View next topic | 
	
	
		| Author | Message | 
	
		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
 | 
			
				|  Posted: Wed May 31, 2017 5:29 am    Post subject: May 31 VH |   |  
				| 
 |  
				|  	  | Code: |  	  | +--------------+----------+---------------+
 | 1   4  238   | 9  27  6 | 237  5   2378 |
 | 7   5  29    | 3  4   8 | 29   6   1    |
 | 268 89 23689 | 17 127 5 | 4    279 2378 |
 +--------------+----------+---------------+
 | 68  2  678   | 4  38  1 | 379  79  5    |
 | 4   3  17    | 56 56  9 | 127  8   27   |
 | 9   18 5     | 2  38  7 | 136  4   36   |
 +--------------+----------+---------------+
 | 25  19 4     | 8  19  3 | 2567 27  267  |
 | 3   6  28    | 57 57  4 | 28   1   9    |
 | 58  7  19    | 16 169 2 | 58   3   4    |
 +--------------+----------+---------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 
 
  	  | Quote: |  	  | took me 2 steps 1) XY-Wing (29-8)=> -8r13c3
 2) X-Wing (2)r28=> -2r13c3,r157c7
 | 
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| ZeroAssoluto 
 
 
 Joined: 05 Feb 2017
 Posts: 1019
 Location: Rimini, Italy
 
 | 
			
				|  Posted: Wed May 31, 2017 7:15 am    Post subject: |   |  
				| 
 |  
				| Hi everyone, 
 I also in two steps
 
 
  	  | Quote: |  	  | X-Wing with number 2 in r28c37 and -2 in r1c37, r3c3, r5c7 and r7c7; W-Wing with 3,8 in r3c9 and r6c5 connected by number 8 in r36c2 and -3 in r6c9.
 | 
 
 Ciao Gianni
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Wed May 31, 2017 8:17 am    Post subject: |   |  
				| 
 |  
				| Hi everyone 
 X wing 2  ( line 2 and line 8 )-->-2R1C3 -2R3C3 -2R7C7 -2R1C7 -2R5C7
 
 AIC R8C3<8>R9C1=8=>R4C1<8>R4C1=6=>R4C3<6>R3C3=6=>R3C3<8>-8 R3C3
 
 AIC R8C3<8>R9C1=8=>R4C1<8>R4C1=6=>R4C3<6>R3C3=6=>R3C3<3>R1C3=3=>R1C3<8>-8 R1C3
 
 Ciao a tutti
 Paolo
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Wed May 31, 2017 3:34 pm    Post subject: |   |  
				| 
 |  
				| Hi everyone 
 Sorry for mistakes on formulas.
 
 Correct formulas
 X wing 2 ( line 2 and line 8 )-->-2R1C3 -2R3C3 -2R7C7 -2R1C7 -2R5C7
 
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠8=>-8 R3C3
 
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠3=>R1C3=3=>R1C3≠8=>-8 R1C3
 
 Ciao a tutti
 Paolo
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
 | 
			
				|  Posted: Wed May 31, 2017 5:45 pm    Post subject: |   |  
				| 
 |  
				| +--------------+----------+---------------+ | 1   4  238   | 9  27  6 | 237  5   2378 |
 | 7   5  29    | 3  4   8 | 29   6   1    |
 | 268 89 23689 | 17 127 5 | 4    279 2378 |
 +--------------+----------+---------------+
 | 68  2  678   | 4  38  1 | 379  79  5    |
 | 4   3  17    | 56 56  9 | 127  8   27   |
 | 9   18 5     | 2  38  7 | 136  4   36   |
 +--------------+----------+---------------+
 | 25  19 4     | 8  19  3 | 2567 27  267  |
 | 3   6  28    | 57 57  4 | 28   1   9    |
 | 58  7  19    | 16 169 2 | 58   3   4    |
 +--------------+----------+---------------+
 
 
  	  | Quote: |  	  | Correct formulas X wing 2 ( line 2 and line 8 )-->-2R1C3 -2R3C3 -2R7C7 -2R1C7 -2R5C7
 
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠8=>-8 R3C3
 
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠3=>R1C3=3=>R1C3≠8=>-8 R1C3
 | 
 
 Paolo,
 
 What are you trying to tell us with the two AICs? Do they get performed consecutively? The first one says r3c3<>8 and the second one, r1c3<>8. What does it all mean? What is your solution to the puzzle?
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Wed May 31, 2017 8:26 pm    Post subject: |   |  
				| 
 |  
				|  	  | Code: |  	  | +--------------+----------+---------------+
 | 1   4  238   | 9  27  6 | 237  5   2378 |
 | 7   5  29    | 3  4   8 | 29   6   1    |
 | 268 89 23689 | 17 127 5 | 4    279 2378 |
 +--------------+----------+---------------+
 | 68  2  678   | 4  38  1 | 379  79  5    |
 | 4   3  17    | 56 56  9 | 127  8   27   |
 | 9   18 5     | 2  38  7 | 136  4   36   |
 +--------------+----------+---------------+
 | 25  19 4     | 8  19  3 | 2567 27  267  |
 | 3   6  28    | 57 57  4 | 28   1   9    |
 | 58  7  19    | 16 169 2 | 58   3   4    |
 +--------------+----------+---------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 After x wing and insert single 2
 
  	  | Code: |  	  | +-------------+----------+------------+
 | 1   4  38   | 9  2   6 | 37  5  378 |
 | 7   5  29   | 3  4   8 | 29  6  1   |
 | 268 89 3689 | 17 17  5 | 4   29 38  |
 +-------------+----------+------------+
 | 68  2  678  | 4  38  1 | 379 79 5   |
 | 4   3  17   | 56 56  9 | 17  8  2   |
 | 9   18 5    | 2  38  7 | 136 4  36  |
 +-------------+----------+------------+
 | 25  19 4    | 8  19  3 | 567 27 67  |
 | 3   6  28   | 57 57  4 | 28  1  9   |
 | 58  7  19   | 16 169 2 | 58  3  4   |
 +-------------+----------+------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 It sufficient for solution only second AIC -8 in R1C3.
 
  	  | Code: |  	  | +-------------+----------+------------+
 | 1   4  3    | 9  2   6 | 37  5  378 |
 | 7   5  29   | 3  4   8 | 29  6  1   |
 | 268 89 3689 | 17 17  5 | 4   29 38  |
 +-------------+----------+------------+
 | 68  2  678  | 4  38  1 | 379 79 5   |
 | 4   3  17   | 56 56  9 | 17  8  2   |
 | 9   18 5    | 2  38  7 | 136 4  36  |
 +-------------+----------+------------+
 | 25  19 4    | 8  19  3 | 567 27 67  |
 | 3   6  28   | 57 57  4 | 28  1  9   |
 | 58  7  19   | 16 169 2 | 58  3  4   |
 +-------------+----------+------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 Solution
 
  	  | Code: |  	  | +-------------+----------+--------------+
 | 1   4  3    | 9  2   6 | 7    5   8   |
 | 7   5  9    | 3  4   8 | 2    6   1   |
 | 2   8  6    | 1  7   5 | 4    9   3   |
 +-------------+----------+--------------+
 | 6   2  8    | 4  3   1 | 9    7   5   |
 | 4   3  7    | 5  6   9 | 1    8   2   |
 | 9   1  5    | 2  8   7 | 3    4   6   |
 +-------------+----------+--------------+
 | 5   9  4    | 8  1   3 | 6    2   7   |
 | 3   6  2    | 7  5   4 | 8    1   9   |
 | 8   7  1    | 6  9   2 | 5    3   4   |
 +-------------+----------+--------------+
 
 | 
 Play this puzzle online at the Daily Sudoku site
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Wed May 31, 2017 8:40 pm    Post subject: |   |  
				| 
 |  
				| Hi Marty R. 
 The logic of two AIC is the same.
 
 When 8 in r8c3 is made in turn true and false the 8 in R1C3 and R3C3 is
 always false, there is a contradiction, so 8 in R1C3 and R3C3 can be removed.
 
 Ciao a tutti
 Paolo
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
 | 
			
				|  Posted: Wed May 31, 2017 11:25 pm    Post subject: |   |  
				| 
 |  
				|  	  | Quote: |  	  | It sufficient for solution only second AIC -8 in R1C3. | 
 
 Sorry to be such a pest with all these questions. If  after the X-Wing, AIC #2 is sufficient, what is the purpose of #1 and why show it? What is the reader to think?
 
 
  	  | Quote: |  	  | When 8 in r8c3 is made in turn true and false the 8 in R1C3 and R3C3 is always false, there is a contradiction, so 8 in R1C3 and R3C3 can be removed.
 | 
 
 I do not understand anything about this sentence. Do you know how to write Eureka notation? That can answer a lot of questions and show exactly what is being done.
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Thu Jun 01, 2017 7:56 am    Post subject: |   |  
				| 
 |  
				| Dear Marty 
 The first puzzle is in my previous post is the initial problem that you put .
 The second puzzle represents the situation  after the  x-wing of the 2 and
 other insertions and eliminations with basic strategies, including the 2 in first line (R1C5).
 The third puzzle is simply obtained by eliminating the 8 in R1C3 which easily leads to the solution.
 The fourth is the solution.
 
 Last edited by Ajò Dimonios on Thu Jun 01, 2017 8:29 am; edited 1 time in total
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Thu Jun 01, 2017 8:27 am    Post subject: |   |  
				| 
 |  
				|  	  | Quote: |  	  | When 8 in r8c3 is made in turn true and false the 8 in R1C3 and R3C3 is always false, there is a contradiction, so 8 in R1C3 and R3C3 can be removed.
 | 
 
 It is simply a demonstration of the logical process of the AIC chain leading to the elimination of the 8 in R1C3 and R3C3.
 
 In fact, the 8 in R8C3 "sees" both 8 in R1C3 and R3C3. So when R8C3 = 8 is true the other 8 are false (weak inference).
 
 
 The second is the strong inference of the AIC chain
 
  	  | Quote: |  	  | AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠8=>-8 R3C3 
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠3=>R1C3=3=>R1C3≠8=>-8 R1C3
 
 | 
 
 Which shows that when R8C3 is false even 8 in R1C3 and R3C3 are false.Then 8 in R1C3 and R3C3 can be eliminated because either that 8 in R8C3 is true or false the 8 in R1C3 and r3C3 are always false (contradiction).
 
 I hope I have been clear, even though my English is not very correct.
 Ciao a Tutti
 Paolo
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Marty R. 
 
 
 Joined: 12 Feb 2006
 Posts: 5770
 Location: Rochester, NY, USA
 
 | 
			
				|  Posted: Thu Jun 01, 2017 11:47 am    Post subject: |   |  
				| 
 |  
				| I hope that this is my final post in this thread. 
 
  	  | Quote: |  	  | The second is the strong inference of the AIC chain Quote:
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠8=>-8 R3C3
 
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠3=>R1C3=3=>R1C3≠8=>-8 R1C3
 
 | 
 
 Is this considered two branches of one chain?
 
 
 
 
  	  | Quote: |  	  | Which shows that when R8C3 is false even 8 in R1C3 and R3C3 are false.Then 8 in R1C3 and R3C3 can be eliminated because either that 8 in R8C3 is true or false the 8 in R1C3 and r3C3 are always false (contradiction) | 
 
 You talk about r8c3 being true or false but I don't see any chain with r8c3=8 being the opening premise.
 
 Yes, r1c3 and r3c3<>8 when r8c3 is either true or false. I don't understand where the contradiction is. it looks to me like a common outcome of a forcing chain.
 
 Is that the solution, that both r1r3c3 and r3c3 are false? Does the elimination of those two 8s finish the puzzle?
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Thu Jun 01, 2017 4:42 pm    Post subject: |   |  
				| 
 |  
				|  	  | Quote: |  	  | AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠8=>-8 R3C3
 
 AIC R8C3≠8=>R9C1=8=>R4C1≠8=>R4C1=6=>R4C3≠6=>R3C3=6=>R3C3≠3=>R1C3=3=>R1C3≠8=>-8 R1C3
 | 
  	  | Quote: |  	  | Is this considered two branches of one chain? | 
 No, there are two independent AICs that share the initial cell and the first part to cell R3C3 = 6. One eliminates 8 in R1C3 and the other eliminates 8 in R3C3.
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Thu Jun 01, 2017 4:55 pm    Post subject: |   |  
				| 
 |  
				|  	  | Quote: |  	  | You talk about r8c3 being true or false but I don't see any chain with r8c3=8 being the opening premise. | 
 The premise is implicit in the fact that 8 in R3C8 "sees" the cells R1C3 and R3C3. This means that there is a weak inference between them.
 In each AIC, the head and tail of the chain must "see" the cells where the elimination occurs.
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Thu Jun 01, 2017 5:08 pm    Post subject: |   |  
				| 
 |  
				|  	  | Quote: |  	  | Yes, r1c3 and r3c3<>8 when r8c3 is either true or false. I don't understand where the contradiction is. it looks to me like a common outcome of a forcing chain. | 
 With contradiction I mean an impossible situation. Cell R1C3 and R3C3 cell can never contain 8 as a value, because it is impossible that in cell R8C3 the 8 is both true and false at the same time (premise of logical reasoning).
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		| Ajò Dimonios 
 
 
 Joined: 01 May 2017
 Posts: 339
 Location: Sassari Italy
 
 | 
			
				|  Posted: Thu Jun 01, 2017 5:22 pm    Post subject: |   |  
				| 
 |  
				|  	  | Quote: |  	  | Is that the solution, that both r1r3c3 and r3c3 are false? Does the elimination of those two 8s finish the puzzle? | 
 As I said in a previous post, to reach the solution is enough to eliminate 8 in R1C3.The second elimination is supposed to be easily accessed by the basic technique
 
 Saluti a tutti
 Paolo
 |  | 
	
		| Back to top |  | 
	
		|  | 
	
		|  |