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Jun 22 VH

 
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ZeroAssoluto



Joined: 05 Feb 2017
Posts: 868
Location: Rimini, Italy

PostPosted: Wed Jun 21, 2017 10:47 pm    Post subject: Jun 22 VH Reply with quote

Hi everyone,

Code:

+-----------+-----------+---------------+
| 8  3   1  | 2  47  6  | 57  457  9    |
| 29 29  4  | 1  78  5  | 3   6    78   |
| 6  5   7  | 3  48  9  | 18  2    148  |
+-----------+-----------+---------------+
| 24 124 5  | 9  6   3  | 178 1478 1478 |
| 3  14  89 | 7  25  28 | 15  1459 6    |
| 7  6   89 | 58 1   4  | 2   359  35   |
+-----------+-----------+---------------+
| 49 489 2  | 58 359 1  | 6   3578 3578 |
| 5  7   6  | 4  23  28 | 9   138  138  |
| 1  89  3  | 6  59  7  | 4   58   2    |
+-----------+-----------+---------------+

Play this puzzle online at the Daily Sudoku site

Quote:
W-Wing 5,8 in r7c4, r9c8 connected by number 8 in r79c2 and -5 in r7c89 and r9c5
XY-Wing 5,8,9 in r7c4, r9c25 and -8 in r7c2


Ciao Gianni
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu Jun 22, 2017 5:25 am    Post subject: Reply with quote

Code:

+-----------+-----------+---------------+
| 8  3   1  | 2  47  6  | 57  457  9    |
| 29 29  4  | 1  78  5  | 3   6    78   |
| 6  5   7  | 3  48  9  | 18  2    148  |
+-----------+-----------+---------------+
| 24 124 5  | 9  6   3  | 178 1478 1478 |
| 3  14  89 | 7  25  28 | 15  1459 6    |
| 7  6   89 | 58 1   4  | 2   359  35   |
+-----------+-----------+---------------+
| 49 489 2  | 58 359 1  | 6   3578 3578 |
| 5  7   6  | 4  23  28 | 9   138  138  |
| 1  89  3  | 6  59  7  | 4   58   2    |
+-----------+-----------+---------------+

Play this puzzle online at the Daily Sudoku site

XY-Wing (59-8) pivot r9c5=> -8r7c2

Potential Deadly Pattern (29-24-49) r247c12
1r4c2=8r7c2-(8=5)r7c4-(5=8)r6c4-(8=9)r6c3-(9=351)r6c89,r5c7=> -1r5c2
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Ajò Dimonios



Joined: 01 May 2017
Posts: 339
Location: Sassari Italy

PostPosted: Thu Jun 22, 2017 12:52 pm    Post subject: Reply with quote

Hi everyone

My solution with one step

Quote:
[(5)R6C4-(5)R6C9=(5)R7C9-(5)R9C8 and (5)R6C4-(5=8 )-(8)R8C6=(8)R8C89-(8)R9C8)]=>R9C8=Ø=>-5R6C4=>stte


Ciao a tutti
Paolo
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu Jun 22, 2017 5:51 pm    Post subject: Reply with quote

Quote:

[(5)R6C4-(5)R6C9=(5)R7C9-(5)R9C8 and (5)R6C4-(5=8 )-(8)R8C6=(8)R8C89-(8)R9C8)]=>R9C8=Ø=>-5R6C4=>stte


Paolo,

Help me understand. I think I can follow until the part I've highlighted in red.
I think it says that r8c8 or 9 is 8, then r9c8 is not 8, then I don't know what this means: R9C8=Ø and then it concludes with r6c4<>5.
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Ajò Dimonios



Joined: 01 May 2017
Posts: 339
Location: Sassari Italy

PostPosted: Thu Jun 22, 2017 7:49 pm    Post subject: Reply with quote

Hi Marty


Quote:
[(5)R6C4-(5)R6C9=(5)R7C9-(5)R9C8 and (5)R6C4-(5=8 )-(8)R8C6=(8)R8C89-(8)R9C8)]=>R9C8=Ø=>-5R6C4=>stte
Quote:
Help me understand. I think I can follow until the part I've highlighted in red.
I think it says that r8c8 or 9 is 8, then r9c8 is not 8, then I don't know what this means: R9C8=Ø and then it concludes with r6c4<>5.

Quote:


The two logical chains both start from the hypothesis that R6C4 is equal to 5. Both lead to a negation, R9C8 <> 5 and R9C8 <> 8, for this reason in the cell R9C8 no candidate can be entered and is therefore empty. At this point the initial hypothesis R6C4 = 5 is certainly false. With the Ø symbol I simply wanted to indicate that the cell R9C8 becomes an empty set (set theory).


Ciao a tutti
Paolo
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA

PostPosted: Thu Jun 22, 2017 10:26 pm    Post subject: Reply with quote

Quote:

The two logical chains both start from the hypothesis that R6C4 is equal to 5.


OK, I did not notice that there were two chains in there.
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