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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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 Posted: Fri Nov 12, 2021 9:51 am Post subject: Nov 12 VH |
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| Code: |
+------------+-------------+---------+
| 7 8 356 | 136 36 9 | 156 2 4 |
| 25 1 9 | 4 8 26 | 56 3 7 |
| 34 236 346 | 5 7 1236 | 16 9 8 |
+------------+-------------+---------+
| 25 25 8 | 9 1 7 | 4 6 3 |
| 9 36 7 | 2 4 36 | 8 1 5 |
| 1 4 36 | 36 5 8 | 9 7 2 |
+------------+-------------+---------+
| 34 9 134 | 13 2 5 | 7 8 6 |
| 6 7 2 | 8 9 4 | 3 5 1 |
| 8 35 135 | 7 36 136 | 2 4 9 |
+------------+-------------+---------+
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Play this puzzle at the Daily Sudoku site
This reminded me of looking a bit like a W wing
r3c6 <> 1
as then r3c7=6, <36> pair in r1c45 leaves no space for a 6 in box 1 |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Nov 12, 2021 11:06 am Post subject: |
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Yes. If we start with the ANP <136> in r1c45
(1=36)r1c45-r2c6=r2c7-(6=1)r3c7 ==> r3c6 < > 1 |
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Earl
Joined: 30 May 2007
Posts: 677
Location: Victoria, KS
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| Posted: Fri Nov 12, 2021 12:37 pm Post subject: Nov 12 VH |
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Not very elegant two step:
346xyzwing@R3C3, -3R!C3
then: 456xywing@R2C1. -6R1C5
Early Earl
PS Sorry, it is 256xywing. Another senior moment.
Last edited by Earl on Sat Nov 13, 2021 1:49 pm; edited 1 time in total |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Nov 12, 2021 1:20 pm Post subject: |
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| I think it is perfectly elegant, Earl. |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Nov 12, 2021 2:55 pm Post subject: Re: Nov 12 VH |
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| Earl wrote: | 456xywing@R2C1. -6R1C5
Early Earl |
Do you mean 256 xy wing ? |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Fri Nov 12, 2021 3:00 pm Post subject: |
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Just about to say the same thing!
Spoooooky |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Fri Nov 12, 2021 3:03 pm Post subject: |
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| Also just noticed that r1c7 <> 1 with the same logic as the start post |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Nov 12, 2021 5:29 pm Post subject: |
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| TomC wrote: | | Also just noticed that r1c7 <> 1 with the same logic as the start post |
Yes - or just extend the same chain as above by one link
(1=36)r1c45-(6)r2c6=r2c7-(6=1)r3c7-r1c7
Whether the ANP is 1 or 36 then r1c7 < > 1 |
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TomC
Joined: 30 Oct 2020
Posts: 358
Location: Wales
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| Posted: Fri Nov 12, 2021 7:23 pm Post subject: |
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What if you don't use the ANP and say if r3c6=1, r2c6=2, r2c1=5, r2c7=6 and then r3c7 is back to 1
(Which is how I saw it the first time, before I noticed the W wing similarity) |
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Mogulmeister
Joined: 03 May 2007
Posts: 1151
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| Posted: Fri Nov 12, 2021 11:19 pm Post subject: |
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You don't have to use the ANP. Batman's teeth. Of course it still shows R3c7 as 1 but other chains are there of course.
So have a go at notating it - Eureka! One of the common languages of sudoku - others are available (eg Snyder).
(1-236)r3c6=(2-6)r2c6-(2=5)r2c1-(5=6)r2c7-(6=1)r3c7 so r3c7 = 1
Which of course also proves that r3c6 can not be 1 |
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