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Daily Telegraph Diabolical Fri, 7-Sep-2012

 
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arkietech



Joined: 31 Jul 2008
Posts: 1834
Location: Northwest Arkansas USA
PostPosted: Mon Sep 10, 2012 5:24 am    Post subject: Daily Telegraph Diabolical Fri, 7-Sep-2012 Reply with quote
Code:

 *-----------*
 |3..|..9|8..|
 |8..|1..|.53|
 |...|...|61.|
 |---+---+---|
 |5..|.4.|...|
 |46.|...|.87|
 |...|...|..2|
 |---+---+---|
 |.41|...|...|
 |27.|..4|..5|
 |..5|7.3|..1|
 *-----------*
 

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Clement



Joined: 24 Apr 2006
Posts: 1113
Location: Dar es Salaam Tanzania
PostPosted: Mon Sep 10, 2012 7:04 am    Post subject: Daily Telegraph Diabolical Fri, 7-Sep-2012 Reply with quote
Code:

+--------+--------------+----------+
| 3  1 6 | 25  257  9   | 8   27 4 |
| 8  9 4 | 1   267  267 | 27  5  3 |
| 7  5 2 | 4   3    8   | 6   1  9 |
+--------+--------------+----------+
| 5  2 8 | 39  4    17  | 13  39 6 |
| 4  6 9 | 235 25   125 | 135 8  7 |
| 1  3 7 | 569 8    56  | 45  49 2 |
+--------+--------------+----------+
| 69 4 1 | 256 2569 256 | 37  37 8 |
| 2  7 3 | 8   1    4   | 9   6  5 |
| 69 8 5 | 7   69   3   | 24  24 1 |
+--------+--------------+----------+
Type 1 UR 69 in Grid r79c15; r7c5<>69 solves it.
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tlanglet



Joined: 17 Oct 2007
Posts: 2468
Location: Northern California Foothills
PostPosted: Mon Sep 10, 2012 1:27 pm    Post subject: Reply with quote
Another AUR solution is

AUR(25)r15c45[7r1c5=3r5c4]-r5c7=r7c7-(3=7)r7c8; -7r1c8

Ted
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Marty R.



Joined: 12 Feb 2006
Posts: 5770
Location: Rochester, NY, USA
PostPosted: Mon Sep 10, 2012 3:48 pm    Post subject: Reply with quote
Code:
+--------+--------------+----------+
| 3  1 6 | 25  257  9   | 8   27 4 |
| 8  9 4 | 1   267  267 | 27  5  3 |
| 7  5 2 | 4   3    8   | 6   1  9 |
+--------+--------------+----------+
| 5  2 8 | 39  4    17  | 13  39 6 |
| 4  6 9 | 235 25   125 | 135 8  7 |
| 1  3 7 | 569 8    56  | 45  49 2 |
+--------+--------------+----------+
| 69 4 1 | 256 2569 256 | 37  37 8 |
| 2  7 3 | 8   1    4   | 9   6  5 |
| 69 8 5 | 7   69   3   | 24  24 1 |
+--------+--------------+----------+


I also used the almost Type 6 UR on 25 in boxes 25. Either r1c5=7 or r5c4=3. The 7 proves a 3 or the 3 proves a 7 and either set of pincers solves it.

(This grid copied from above can eliminate a few candidates based on the 39 pair in r4.
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